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4 years ago

Can someone please help me i don’t know this and i’m really stuck so please

Mathematics

1 answer:

ratelena [41]4 years ago

6 0

Joaquin can send between at most 250 text messages per month. Since he has already sent 141, we must have
.. 141 +t ≤ 250

The solution to this model of the situation can be found by subtracting 141.
.. t ≤ 109

We graph the lower limit as zero because we know Joaquin cannot send a negative number of text messages.

Interpretation:
Joaquin can send between 0 and 109 additional text messages this month.

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How many kilometers are in 60 miles? Note: There are 1.609kms in 1mi.

kozerog [31]

Answer:

Your answer is 96.5606 Kilometers.

Step-by-step explanation:

1.609 x 60 = 96.5606

Mark as brainliest if it's correct!

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 200? O2./10 1012 10./20 1002

solong [7]

Hey there!

We know options. B and D aren't going to be your answer because they are way too big to be equivalent to 200

In order for you to find out which one is equivalent to 200 you have to calculate you late the options until you get to 200 and then you could do process of elimination!

It can't be A because 2/10 = 0.20 aka 20%

It can't be option. C because 10/20 = 0.50 aka 50%

So none of the above would be your answer

The correct answer would most likely be: 10√2

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

8 0

3 years ago

To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?

ad-work [718]

Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

$(-2\sqrt{20k})(5\sqrt{8k^3})$

First we will simplify the first factor,

$-2\sqrt{20k}$

We will write 20 as a product of factors:

$-2\sqrt{4*5k}$

We know the square root of 2 is 2, so we pull a 2 out:

$-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}$

Now we will simplify the second factor,

$5\sqrt{8k^3}$

We will rewrite 8 as a product of factors, as well as the variable:

$5\sqrt{2*4*k^2*k}$

The square root of 2 is 2, so we pull a 2 out. Additionally, the square root of k² is k, so we pull that out:

$5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}$

This gives us the product

$(-4\sqrt{5k})(10k\sqrt{2k})$

Multiplying the coefficients, we have

$-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})$

Multiplying the two radicals, we have

$-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}$

The square root of k² is k, so we pull a k out, leaving

$-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}$

8 0

4 years ago

Read 2 more answers

Is 8/5 proportional to 24/15 ?

DiKsa [7]

Hey there!

The answer to your question is, yes, it is

Given:

$\frac{8}{5}$ $and$ $\frac{24}{15}$

To see if they are equal, we can use cross products (see below for information about this, if you don't know what it is). Let us assume they are equal. This would mean that:

$8*15=24*5$

Let's solve it and see if it is true:

$8*15=24*5$

$120=120$

Therefore, they are proportional.

Cross products

WORD DEFINITION:

Given two fractions, you can take the numerator of the first fraction multiplied by the denominator of the second fraction and it should equal the denominator of the first fraction multiplied by the numerator of the second fraction.

ALGEBRAIC DEFINITION:

Given two fractions, $\frac{a}{b}$ $and$ $\frac{c}{d}$ , $a*d$ should equal to $b*c$