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3 years ago

Why is 3 + (−5) equal to −2?

2 answers:

5 0

It is not equal to -2 because the five is a negative so when adding two different integers are subtracted and with a negative sign.

Brilliant_brown [7]3 years ago

4 0

If u add 3 to negative 5 you will be left with a negative number which is 3

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(6x^2-5x+3)+(3x^2+7x-8)<br><br>add

Mrac [35]

Answer:

$9 {x}^{2} + 2x - 5$

Step-by-step explanation:

I have answered ur question

8 0

3 years ago

Four times a number increased by 3 is -89

sp2606 [1]

Answer:

-21.5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the

s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

$F(x)=\sqrt{x-2}$

$G(x)=(x-2)^2$

$H(x)=x^2+2$

We compose F(x) and G(x) to get:

$(F\circ G)(x)=F(G(x))$

$(F\circ G)(x)=F((x-2)^2)$

$(F\circ G)(x)=\sqrt{(x-2)^2-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+4-2}$

$(F\circ G)(x)=\sqrt{x^2-4x+2}$

$(F\circ G)(x)\ne x$

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

$(F\circ H)(x)=F(H(x))$

$(F\circ H)(x)=F(x^2+2)$

$(F\circ H)(x)=\sqrt{x^2+2-2}$

We simplify to get:

$(F\circ H)(x)=\sqrt{x^2}$

$(F\circ H)(x)=x$

Since $(F\circ H)(x)=x$ , H(x) is an inverse of F(x)

3 0

3 years ago

Current rules for telephone area codes allow the use of digits 2-9 for the first digit, and 0-9 for the second and third dig

Anna35 [415]

Using the fundamental counting theorem, we have that:

648 different area codes are possible with this rule.
There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

8 options for the first digit.
9 options for the second and third.

Thus:

$8 \times 9 \times 9 = 648$

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

7 digits, each with 10 options.
648 different area codes.

Then

$648 \times 10^7 = 6,480,000,000
$

There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0

2 years ago

The ratio of cats to dogs at April's Animal Shelter was 3 to 2. How many dogs were in the shleter if there were a total of 75 ca

DochEvi [55]

Answer:

A:30

Step-by-step explanation:

because 3+2(the ratio) =5

75(the total number or both) divide by 5

so 1 ratio=15

15 x 2(the ratio of dogs)

=30

3 0

2 years ago