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8090 [49]
3 years ago
15

Select the graph that represent the equation (x-6)^2+(y+7)^2=16

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

Answer:

Given equation

(x-6)^2+(y+7)^2=16

centre (6,-7)  and radius 4.

Step-by-step explanation:

The equation of a circle is (x - a)² + (y - b)² = r²

the radius is r

the centre is (a, b)

<u>Given equation </u>

(x-6)^2+(y+7)^2=16

so ,

a = 6

b = - 7

r² = 16

r = \pm \sqrt{16}

r = 4

Therefore,  the circle with centre (6,-7)  and radius 4.

Mumz [18]3 years ago
3 0

Answer:

This is a circle with centre (6,-7)  and radius 4.

Step-by-step explanation:

The equation of a circle has the following format:

(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}

In which r is the radius(half the diameter) and the centre is the point (x_{0}, y_{0})

In this question:

(x-6)^{2} + (y+7)^{2} = 16

So

x_{0} = 6, y_{0} = -7

r^{2} = 16

r = \pm \sqrt{16}

The radius is the positive value.

r = 4

So this is a circle with centre (6,-7)  and radius 4.

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