Answer:
The correct option is A
Explanation:
In project management, earliest finish time for activity A refers to the earliest start time for succeeding activities such as B and C to start.
Assume that activities A and B comes before C, the earliest finish time for C can be arrived at by computing the earliest start-finish (critical path) of the activity with the largest EF.
That is, if two activities (A and B) come before activity C, one can estimate how long it's going to take to complete activity C if ones knows how long activity B will take (being the activity with the largest earliest finish time).
Cheers!
Answer:
Regulus is the most luminous. Regulus is the least luminous
Explanation:
- Transcribed image text: Of the three stars you've observed (HIP 87937, HIP 108870, and Tau Cet), which one is more luminous?
- View Available Hint(s) Tau Cet O HIP 87937 O HIP 108870
- They have the same luminosity.
To learn more about it, refer
to https://brainly.in/question/413163
#SPJ4
Answer:
Option d) is correct
Explanation:
To optimize the processing of a warehouse’s operations, products are stored on warehouse racks when they arrive. The items that arrive last are the first to go out to minimize the time it takes to retrieve an item. The items that arrive need to be represented and the warehouse should be left in a data structure. The data structure which should you use to represent this situation is a queue.
Option d) is correct
Answer:
#include <math.h>
#include <stdio.h>
#include <string.h>
#define BASE 3
#define NRQUESTIONS 15
void toABC(int n, char* buf, int base, int size) {
memset(buf, 'A', size);
buf[size] = 0;
while (n && size) {
buf[--size] = 'A' + (n % base);
n /= base;
}
}
int main()
{
char buf[16];
for (int i = 0; i < pow(BASE, NRQUESTIONS); i++) {
toABC(i, buf, BASE, NRQUESTIONS);
printf("%s\n", buf);
}
}
Explanation:
Assuming 3 is the number of possible answers to choose from for each question.
I tackled this by having an integer counter enumerate all values from 0 to 3^15, and then convert each integer to a base-3 representation, using ABC in stead of 012.
Answer:
# user is prompted to enter the value of n
n = int(input("Enter your number: "))
# if statement to check if n > 0
if (n > 0):
# for-loop to loop through the value of n
for digit in range(1, (n+1)):
# if digit is odd, print 1
if((digit % 2) == 1):
print("1", end=" ")
# else if digit is even print 0
else:
print("0", end=" ")
Explanation:
The code is written in Python and is well commented.
A sample output of the code execution is attached.
