A shipment of racquetballs with a mean diameter of 60 mm and a standard deviation of 0.9 mm is normally distributed. By how many
1 answer:
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Answer:
m = 11
Step-by-step explanation:
Given
(m + 4) = 6 ← multiply both sides by 5 to clear the fraction
2(m + 4) = 30 ( divide both sides by 2 )
m + 4 = 15 ( subtract 4 from both sides )
m = 11
This method avoids having to deal with awkward fractions