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mash [69]
3 years ago
15

Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your

solution and tell why you chose that strategy. x^2+4=0 Problem 1 Hint: directions say if possible (so as you solve think about a step that you get to that prevents you from solving for the final answer). Explain your thoughts. x^2+x-6=0 Problem 2 Hint: Factor the equation and then solve to get 2 answers using the zero product property x^2-6x+7=0 Problem 3 Hint: factor using the completing the square method
Mathematics
2 answers:
marishachu [46]3 years ago
7 0
Problem 1: x^2 + 4 = 0 , x^2 = -4 , this problem has no real solution because x = 2i which is an imaginary number

problem 2: x^2 +x -6 = 0 ,  (x + 3)(x - 2) =0 , x = 2 or x = -3

problem 3: x^2 -6x +7 =0 , (x^2 -6x +9) - 2 =0 , (x - 3)^2 = 2 , x-3 = √2 , x = 3+√2  or x - 3 = -√2 , x = 3 - √2
damaskus [11]3 years ago
6 0
1)
x^2 + 4 = 0      Subtract 4 from each side
x^2 = -4           
You cannot square a number to get a negative number. No real solution. (If you have learned about imaginary numbers, answer is 2i)

2)
<span>x^2+x-6=0        Factor. 3 and -2 add up to 1, and multiply to -6
(x+3)(x-2) = 0   
Zero Product Property: Which numbers would put a zero in one of the parentheses?
x = -3 or x=2

3) </span><span>x^2-6x+7=0         
Completing the Square:
Take half of b (-6), square it, and add/subtract that coefficient
x^2 - 6x + 9 - 9 + 7 = 0
(x -3)^2 - 2 = 0         Add 2 to both sides
(x-3)^2</span> = 2               Take the square root of both sides
<span>(x-3) = </span>√2 or -√2       Add 3 to both sides
<span>x = 3 + </span>√2 or 3 - √2<span>

</span>
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It's an overcast day in Hayward and you're waiting for AC Transit 97 Bus Line to show up. Your weather app says there's a 30% ch
melomori [17]

Answer:

a

 P(r n L) =  0.12  

b

 P(L) = 0.225

c

  P(\= r | L) =  0.4667

Step-by-step explanation:

The chance that it will rain is  P(r ) = 0.30

 The chance that it does not rain is P(\= r ) = 1 - P(r )

                                                             P(\= r ) = 1 -0.30

                                                              P(\= r ) = 0.70

The probability that the bus run late if it rains is  P(L | r) =  0.4

 The probability that the bus run late if it does not rain is   P(L | \= r) =  0.15

  Generally the probability that it will rain and the bus will be late is mathematically represented as

     P(r n L) =  P(L | r) *  P(r)

=>  P(r n L) =  0.4 *  0.30

=>  P(r n L) =  0.12  

Generally the probability that the bus will be late is mathematically represented as

     P(L) =  P(r) * P(L|r) + P(L | \= r) * P(\= r)

=>  P(L) =  0.30 * 0.4 +0.15*0.70

 =>  P(L) = 0.225

Generally given that the bus ran late,  the probability that the bus it was not raining is mathematically represented as

      P(\= r | L) =  1- P(r | L )

Here  P(r | L ) = \frac{P(r n L)}{P(L)}

=>   P(r | L ) = \frac{0.12}{0.225}

=>   P(r | L ) = 0.533

So

      P(\= r | L) =  1- 0.533

   =>   P(\= r | L) =  0.467

3 0
3 years ago
Dave goes into a cafe and buys 2 cups of coffee and a piece of cake.
andriy [413]
Dave is correct you add the price of the 2 cups of coffee and piece of cake together 2.75+2.75+2.90= £8.40 then you subtract that from £10 so £10-£8.40= £1.60 which is more then £1.50
6 0
3 years ago
The function f(x) = –2x2 + 32 represents the height of an object, f(x), after x seconds. How many seconds does it take for the o
Law Incorporation [45]

Given:

The height of an object, f(x), after x seconds is

f(x)=-2x^2+32

To find:

The time taken be object to hit the ground.

Solution:

We have,

f(x)=-2x^2+32

The object will hit the ground if the height is 0, i.e., f(x)=0.

0=-2x^2+32

2x^2=32

Divide both sides by 2.

x^2=\dfrac{32}{2}

x^2=16

Taking square root on both sides.

x=\pm 4

Time cannot be negative. So, x=4.

Therefore, the object will hit the ground after 4 seconds.

5 0
3 years ago
How many squares are needed to make the eighth figure in the pattern
Aliun [14]
15 squares are needed to make the eighth figure in the pattern
3 0
4 years ago
Read 2 more answers
CPM homework 8.1.2 problem 8-19
Kisachek [45]

The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.

<h3>What is Area ?</h3>

Area is the space occupied by a two dimensional object,

The area and perimeter of the given shape can be determined by dividing it into basic shapes.

The area and the perimeter of the shape given = Area of the rectangle +Area of upper triangle - Area of two small triangles at the bottom

Area of rectangle = 5 mi * 9 mi = 45 sq.mi

Area of upper Triangle = (1/2) *9*3 = 27/2 sq.mi

Area of small Triangle = (1/2) * 3*6 = 9 sq.mi

Area of other small Triangle = (1/2)*3*3 = 9/2 sq.mi

Area of the figure = 45 +13.5 -9-4.5

Area of the figure =  45 sq.mi

Similarly for Perimeter = Perimeter of the rectangle +Perimeter of upper triangle -Perimeter of two small triangles at the bottom

Perimeter = 28 -(3+6+6.708) -(3+3+4.2426) +(3+9+9.486

Perimeter = 23.5354 mi

Therefore , The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.

To know more about Area

brainly.com/question/27683633

#SPJ1

5 0
2 years ago
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