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Stels [109]
3 years ago
15

G protein‑coupled receptors (GPCRs) and receptor tyrosine kinases (RTKs) are two basic receptor types by which cells transduce s

ignals.
A) Classify each statement as describing GPCRs, RTKs, both types of receptors, or neither of these two types.
1. phosphorylation of receptor can terminate signal or desensitize receptor.
2. autophosphorylation of receptor can initiate signal.
3. structure contains seven transmembrane helices.
4. an example is the insulin receptor.
5. an example is the epinephrine receptor.
6. activate heterotrimeric G proteins directly.
Biology
1 answer:
elena-s [515]3 years ago
5 0
<h2>GPCRs,RTKs</h2>

Explanation:

G Protein Coupled Receptors(GPCRs) are more common and found in almost all eukaryotes whereas Receptor Tyrosine Kinases(RTKs) are second largest family of receptors that relay signal from cell surface to the interior

  1. G protein coupled receptors(GPCRs) interacts with the ligand activated GPCR and phosphorylates its intracellular domain.This process of phosphorylation can terminate signal or desensitize receptor
  2. Autophosphorylation of receptor can initiate signal in case of Receptor Tyrosine Kinases(RTKs);Autophosphorylation is a feature of RTKs in which receptor dimerization activates intrinsic tyrosine kinase activity by which they phosphorylate its own tyrosine residue on cytosolic phase
  3. Seven transmembrane helices can be seen in case of G protein-coupled receptors(GPCRs);transmembrane protein of it consists of single polypeptide and spans the membrane 7 times
  4. Insulin receptor is a part of Insulin Signalling which comes under RTKs;Insulin receptor always exist in case of dimeric form
  5. Epinephrine receptor is an example of GPCRs;Epinephrine is an endocrine hormones produced in stress condition
  6. Transmembrane protein of GPCR activates G protein,activated G protein binds with effector enzyme and activate it;effector enzyme further can produce or destroy secondary messenger
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Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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