Are you looking to reduce this fraction? if so it would be 4/3. hope this helps!
So the first term is 2.7
the second term is 5..4
the thrid term is 10.8
it seems to be doubleing
so the nth term
1th term=2.7
2th term=5.4
we know there must be a power of 2 in there that is influenced by which term it is so
2^n and something more
trial and error
so (1.35)(2^n))
the nth term is (1.35) times (2^n) or 1.35(2^n)
3/10 is the answer, hop you do will in school this year
Hello,
The answer is "59,320"
Reason:
First write the equation:
10+10-10*5932
10+10=20
20-10=10
10*5392=53,920
=59,320
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
Answer:324
Step-by-step explanation:
int i = 42.7; /* konwersja z double do int */
float f = i; /* konwersja z int do float */
double d = f; /* konwersja z float do double */
unsigned u = i; /* konwersja z int do unsigned int */
f = 4.2; /* konwersja z double do float */
i = d; /* konwersja z double do int */
char *str = "foo"; /* konwersja z const char* do char* [1] */
const char *cstr = str; /* konwersja z char* do const char* */
void *ptr = str; /* konwersja z char* do void* */
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