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3 years ago

What’s the correct answer for this question?

Mathematics

1 answer:

Paladinen [302]3 years ago

3 0

The second option.

Basically, you can use SAS.

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Which expression is NOT equivalent to 12 x -3 2/3

satela [25.4K]

Add then multiply b through, e to f, hopethsie helps

4 0

3 years ago

write quadratic equation whose roots are 4 and -3 and whose leading coefficient is 5 use the letter X to represent the variable

AlladinOne [14]

$5(x-4)(x+3)=\\
5(x^2+3x-4x-12)=\\
5(x^2-x-12)=\\
5x^2-5x-60$

5 0

3 years ago

The midpoint of is

Degger [83]

Answer:

The answer is 0/2

Step-by-step explanation:

The second y - the first y / the second x - the first x.

Step 1: 1 - 1 / 5 - 3

Step 2: 0 / 5 - 3

Step 3: 0 / 2

8 0

4 years ago

Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2

valentina_108 [34]

Answer:

Solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2+6x-8=0$ by completing the square method.

For completing the square method: we need to follow: $a^2+2ab+b^2=(a+b)^2$

We are given:

$x^2+6x-8=0$

Solving by completing the square

$x^2+2(x)(?)+(?)^2-8=0$

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

$x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17$

So, solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

7 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

Leona [35]

Answer:

( $\frac{2}{3} , \frac{1}{5}$ )

Step-by-step explanation:

The fastest way to do this is to convert both equations into slope-intercept form and graph it to find the solution point. If you wanted to do this algebraically, you might want to start out by getting rid of the fractions and using either substitution or elimination to find x and y.

4 0

3 years ago