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nydimaria [60]
3 years ago
8

Which option is most likely used to create many-to-many relationships in Access?

Computers and Technology
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

Junction table.

Explanation:

Junction table is most likely used to create many-to-many relationships in Access.

A many-to-many relationship comes into existence when one (1) or more items in a table has a relationship with one (1) or more items in another table. An example is the products in a customer order.

Many-to-many relationships provides users with critical and crucial information, they're the most commonly used table relationships in Access.

In order to represent a many-to-many relationship in Access, a third table should be created by the user, this is often referred to as the junction or linking table, which further disintegrate the many-to-many relationship into a two (2) one-to-many relationships.

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In Scheme, the form (symbol-length? 'James) will return: Group of answer choices 0 5 6 error message
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Answer:

an error message

Explanation:

The return value is the value which is sent back by the function to a place in the code from where the \text{function} was called from. Its main work is to return a value form the function.

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2 years ago
Convert the following numbers from decimal to binary, assuming unsigned binary representation:________.
kumpel [21]

Answer:

Binary representations of following are:

A) 35 = 100011

B) 3 = 11

C) 27 = 11011

D) 16 = 10000

Explanation:

The method to generate the binary number from a decimal is :

Keep on dividing the number by 2 and keep on tracking the remainder

And the quotient is again divided and remainder is tracked so that the number is completely divided.

And then write the binary digits from bottom to top.

Please have a look at the method in below examples:

A) 35

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 35 & 1 \\  2 & 17 & 1 \\   2 & 8 & 0  \\ 2 & 4 & 0  \\ 2 & 2 & 0   \\ 2 & 1 & 1\end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary number is 100011

B) 3

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 3 & 1 \\  2 & 1 & 1 \\  \end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 11.

C) 27

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 27 & 1 \\  2 & 13 & 1 \\   2 & 6 & 0  \\ 2 & 3 & 1  \\ 2 & 1 & 1   \end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 11011.

D) 16

\begin{center}\begin{tabular}{ c c c }Number & Quotient & Remainder\\ 2 & 16 & 0 \\  2 & 8 & 0 \\   2 & 4 & 0  \\ 2 & 2 & 0  \\ 2 & 1 & 1   \\\end{tabular}\end{center}

Writing the remainder from bottom to top.

So, binary equivalent is 10000.

Answers are:

Binary representations of following are:

A) 35 = <em>100011</em>

B) 3 = <em>11</em>

C) 27 = <em>11011</em>

D) 16 = <em>10000</em>

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3 years ago
A(n) _________________________ is a character that word displays on the screen but is not visible on a printed document.
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