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nydimaria [60]
3 years ago
8

Which option is most likely used to create many-to-many relationships in Access?

Computers and Technology
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

Junction table.

Explanation:

Junction table is most likely used to create many-to-many relationships in Access.

A many-to-many relationship comes into existence when one (1) or more items in a table has a relationship with one (1) or more items in another table. An example is the products in a customer order.

Many-to-many relationships provides users with critical and crucial information, they're the most commonly used table relationships in Access.

In order to represent a many-to-many relationship in Access, a third table should be created by the user, this is often referred to as the junction or linking table, which further disintegrate the many-to-many relationship into a two (2) one-to-many relationships.

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How can we style the images and layouts of our pages?
professor190 [17]

Answer

Using CSS and Html:)

Explanation:

4 0
2 years ago
1. Which of the following is not related to a buffer overflow? A. Static buffer overflow B. Index error C. Canonicalization erro
GaryK [48]

Answer: C) Canonicalization error

Explanation:

Canonicalization error is the error or fault that occurs when data is changed into canonical form or standard form that persist different representation.This can create fault when different filenames or structure is assigned to data and canonization cannot take place as it works for simple data representation.

  • Other options are incorrect because static buffer flow is stable writing or reading of data that reaches outside the buffer boundary.Index error is accessing of index by any user that is found beyond the index's list boundary.
  • Heap overflow is the stack gets overlowed outside the boundary while overwriting heap.Thus, the correct option is option(C).
4 0
3 years ago
Convert<br> 0.625 to binary
Anastaziya [24]

\huge{ \rm{Question:}}

Convert

0.625 to binary

\huge{ \rm{Answer:}}

Translate 0.625 into a fraction. We all know that 0.5 is ½. We know that the remainder, 0.125, is ⅛. Add them together, and you get ½ + ⅛ = ⅝.

Now, in binary, the positions to the right of the point are , which is ½, ¼, and ⅛ respectively.

⅝ is 5 × ⅛. 5 in binary is 101. So, ⅝ is

= 0.101

8 0
2 years ago
Write a CashRegister class that can be used with the RetailItem class that you wrote in Chapter 6's Programming Challenge 4. The
lys-0071 [83]

Answer:

Following are the code to this question:

import java.util.*; //import package for user input

class RetailItem//defining class RetailItem  

{

private String desc;//defining String variable

private int unit;//defining integer variable

private double prices;//defining double variable

RetailItem()//defining default Constructor

{

   //Constructor body

}

Output:

The Sub Total value: 199.75

The Sales Tax value: 11.985

The Total value: $211.735

Explanation:

In the above code three class "RetailItem, CashRegister, and Main" is defined, in the class "RetailItem", it defines three variable that is "desc, unit, and prices", inside the class "get and set" method and the constructor is defined, that calculates its value.

In the next step,  class "CashRegister" is defined, and inside the class parameterized constructor is defined, which uses the get and set method to return its value.  

In the next step, the main class is declared, in the main method two-class object is created and calls its method that are "getSubtotal, getTax, and getTotal".  

There is some technical error that's why full code can't be added so, please find the attached file of code.  

7 0
2 years ago
Why is it unlikely that you will find the ip address 192.168.250.10 on the internet?
gayaneshka [121]
That IP address is either Internal, private or reserved
5 0
3 years ago
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