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cluponka [151]
4 years ago
14

Which is equivalent to ? please wait till i add my picture

Mathematics
1 answer:
xeze [42]4 years ago
5 0
The answer is b. 1215^1/5*x  thank you!
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I need the answer to this problem
chubhunter [2.5K]
After making six monthly payments on her car loan, Thomas's savings account will be lower.

6 0
3 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. g(x) = 7x u2 − 1 u2 + 1 du 6x Hint: 7x
VikaD [51]

It looks like you're given

g(x)=\displaystyle\int_{6x}^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du

Then by the additivity of definite integrals this is the same as

g(x)=\displaystyle\int_0^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du-\int_0^{6x}\frac{u^2-1}{u^2+1}\,\mathrm du

(presumably this is what the hint suggests to use)

Then by the fundamental theorem of calculus, we have

\dfrac{\mathrm dg}{\mathrm dx}=7\dfrac{(7x)^2-1}{(7x)^2+1}-6\dfrac{(6x)^2-1}{(6x)^2+1}=\dfrac{1764x^4+169x^2-1}{1764x^4+85x^2+1}

8 0
4 years ago
SOMEONE PLEASE HELPPPPPPPPPP
sweet-ann [11.9K]

Answer:

the formula for the volume of a square pyramid is V=a^2*h/3

so if we just put in the data

12^2*10/3

144*10/3

480

so the answer is B

Hope This Helps!!!

7 0
3 years ago
8) Jennifer has a collection of 1,600 coins. Of the coins, 40% are dated
Kitty [74]
<h3>Answer:  400  (choice A)</h3>

==============================================

Explanation:

40% + 35% = 75% of the coins were either made before 1940, or made from 1940 to 1980. In other words, 75% of the coins were minted before 1980. This leaves 100% - 75% = 25% of the coins to being minted after 1980.

25% of 1600 = 0.25*1600 = 400 coins were made after 1980

4 0
3 years ago
A zoo keeper wants to fence a rectangular habitat for goats. The length of the habitat should be at least 80 feet and the perime
zimovet [89]

Answer:

Step-by-step explanation:

Let x ft be the length of the fence and y ft be the width of the fence.

1. The length of the habitat should be at least 80 feet, then

2. The perimeter of the habitat should be no more than 300 feet. The perimeter of the fences 2x+2y ft, then

3. The system of inequalities that represent the model is

The graph of these inequalities is attached.

Two possible solutions are

1. x=100 ft, y=20 ft (100≥80 and 2·100+2·20=240≤300);

2. x=110 ft, y=30 ft (110≥80 and 2·110+2·30=280≤300).

7 0
3 years ago
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