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Pani-rosa [81]
3 years ago
5

Find either the maximum or the minimum value of the following quadratic equation. Be sure to show all of your work and identify

the maximum or minimum value correctly.
y = 5x^2 - 10x - 4
Mathematics
1 answer:
podryga [215]3 years ago
6 0

Answer:

the minimum is (1,-9)

Step-by-step explanation:

y = 5x^2 - 10x - 4

since the parabola opens upward  5>0, this will have a minimum

it will occur along the axis of symmetry h=-b/2a

y =ax^2 +bx+c

h = -(-10)/2*5

h  = 10/10 =1

the minimum occurs at x =1

the y value for the minimum is calculated by substituting x =1 back into the equation

y = 5 * 1^2 - 10*1 -4

y = 5*1^2 -10 -4

y = 5-10-4

y = -9

the minimum is (1,-9)

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Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
4 years ago
Read 2 more answers
Antoine works in a restaurant and he is paid his regular hourly rate of 40 hours a week and time and a half for all hours over 4
Inessa05 [86]
560+ 147= 707

14(40)= 560
14+ 14(1/2)=21
21(7)= 147
6 0
3 years ago
The graph shows the relationship between the number of months different students practiced tennis and the number of matches they
Andrew [12]

Answer:

1 is 3 and 2 is y 2/1x

Step-by-step explanation:

if you do not understand 2 then here is a explanation you find slope so take any two point then go over then up the amount over is on the bottom and the amount up on top then simplify if needed

3 0
3 years ago
What is the solution to this system of equations?<br> 2x+y−z=−3<br> 5x−2y+2z=24<br> 3x−z=5
raketka [301]

Answer:

x=2

Step-by-step explanation:

7 0
2 years ago
A cone has a diameter of 30 in. and a slant height of 17 in. What is the approximate volume of the cone?
Alex777 [14]
We need to find the height of the cylinder
pythagorean theorem
15 is the bottom leg (30/2=15)
17 is hypotonuse
b=height
15^2+b^2=17^2
225+b^2=289
minus 225 both sides
b^2=64
sqrt both sides b=8

Vcone=(1/3)hpir^2
d/2=r=30/2=15
h=8
V=(1/3)8pi15^2
V=(1/3)8pi225
V=8pi75
V=600pi
aprox pi=3.14159256
V=1884.955536 in^3
round if nececary
7 0
3 years ago
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