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4 years ago

What number can you add to √7 to get a rational number?

Mathematics

2 answers:

gavmur [86]4 years ago

7 0

Answer:

The Answer is : −7√

Step-by-step explanation:

Dmitry [639]4 years ago

5 0

I think 0 can be answer.
if 0 is multiplied to√7 it will become a rational one.

hope this one be correct and helps u

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$200 at 9% compounded semiannually for 2 years

Sav [38]

Answer:

Your answer is on the picture

Step-by-step explanation:

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3 years ago

What is 2x4= (Need help someone)

4vir4ik [10]

The answer is 8, hope this helps :)

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3 years ago

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Paula knows the total cost for 100 students will be $750, and the cost total cost for 150 students is $1050. What is the caterer

Roman55 [17]

Step-by-step explanation:

the price charged for 100 students reflects the cost per student that applies to the order as a whole.

100 * 6 = $600, so the fixed cost is 750-600 = 150.

...

We can check this by substituting in the other equation.

Does 150*6 + 150 = 1050?

150*6=900

900+150 = 1050.

Yes, it does

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We can express this relationship by the equation:

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3 years ago

Rex spent $6.42 at the store. He gave the cashier the money shown above. How much money did Rex get back from the cashier?

cupoosta [38]

The answer is d 10-6.42 is $3.58

4 0

3 years ago

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A padlock has the digits 0 through 9 arranged in a circle on its face. A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is fou

stepan [7]

Answer:

The total numbers of possible combinations are 3430.

Step-by-step explanation:

Consider the provided information.

A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.

Here, for the first digit we have 10 choices.

For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.

For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.

For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.

So the number of choices are:

$10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430$

Hence, the total numbers of possible combinations are 3430.

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3 years ago