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GalinKa [24]
4 years ago
15

Generate the requested sets using only set builder notation and the provided sets. Some problems may require you to build one or

more sets to be used in the generation of other sets. Z, the set of all integers R, the set of all real number a. Form the set that contains only positive, odd integers. b. Form the set {0,1} without testing for a range or if an element is equal to 0 or 1.

Computers and Technology
1 answer:
Elenna [48]4 years ago
5 0

The answer & explanation for this question is given in the attachment below.

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18. Which console pioneered the ability for gamers to save their game and resume from that point?
mina [271]
I think it is D
Hope my answer help
Sorry it is wrong
4 0
3 years ago
HW4:
julsineya [31]

Answer:

Check the explanation

Explanation:

1)

import java.util.*;

public class ArrayStack {

// Declare an Array List

ArrayList<String> aList;

// Constructor that Instantiates arrayList object

ArrayStack() {

aList = new ArrayList<String>();

}

public void push(String object) {

//Add the Value

aList.add(object);

}

public String pop() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// Remove it

ret = aList.get(aList.size() - 1);

aList.remove(aList.size() - 1);

}

return ret;

}

public String peek() {

String ret = null;

//Check the size of list if 0 means Stack is Empty

if (aList.isEmpty())

System.out.println("Stack is Empty");

else {

//Return the last value entered as Stack is LAST IN FIRST OUT

// DO not remove it

ret = aList.get(aList.size() - 1);

}

return ret;

}

public boolean isEmpty() {

//Check the size of list if 0 means Stack is Empty

return aList.size()==0;

}

public static void insertionSort(int arr[], int n)

{

int i, j;

for(i=2;i< n;i++){

arr[0] = arr[i];

j = 1;

while(j <= i-1){

/* implement your code here /*

/* you must start compare arr[j] with a[0], notice that j = 1 */

}

}

}

public static void main(String[] args) {

// TODO Auto-generated method stub

ArrayStack aStack = new ArrayStack();

aStack.push("Hey");

aStack.push("Hello");

aStack.push("Bye");

System.out.println(aStack.pop());

System.out.println("Peek: " + aStack.peek());

System.out.println(aStack.pop());

System.out.println(aStack.isEmpty());

System.out.println(aStack.pop());

// int arr[] = new int[] {3,4,2,1,6,7,5};

// insertionSort(arr,7);

// System.out.println(Arrays.toString(arr));

}

}

LinkedQueue

interface QueueInterface {

public void enqueue(Object item);

// Effect: Adds item to the rear of this queue.

// Precondition: This queue is not full.

// Postcondition: item is at the rear of this queue.

public Object dequeue();

// Effect: Removes front element from this queue and returns it.

// Precondition: This queue is not empty.

// Postconditions: Front element has been removed from this queue.

// Return value = (the removed element)

public boolean isEmpty();

// Effect: Determines whether this queue is empty.

// Postcondition: Return value = (this queue is empty)

public boolean isFull();

// Effect: Determines whether this queue is full.

// Postcondition: Return value = (queue is full)

public int size();

}

public class LinkedQueue implements QueueInterface {

private class QueueNode

// Used to hold references to queue nodes for the linked queue

// implementation

{

private Object info;

private QueueNode link;

}

private QueueNode front; // reference to the front of this queue

private QueueNode rear; // reference to the rear of this queue

public LinkedQueue()

// Constructor

{

front = null;

rear = null;

}

public void enqueue(Object item)

// Adds item to the rear of this queue.

{

QueueNode newNode = new QueueNode();

newNode.info = item;

newNode.link = null;

if (rear == null)

front = newNode;

else

rear.link = newNode;

rear = newNode;

}

public Object dequeue()

// Removes front element from this queue and returns it.

{

Object item;

item = front.info;

front = front.link;

if (front == null)

rear = null;

return item;

}

public boolean isEmpty()

// Determines whether this queue is empty.

{

if (front == null)

return true;

else

return false;

}

public Object peek()

// Determines whether this queue is empty.

{

if (front == null)

return null;

else

return front.info;

}

public int size()

// Determines whether this queue is empty

{

QueueNode curr = front;

int count = 0;

while (curr != null) {

++count;

curr = curr.link;

}

return count;

}

public String toString()

// Determines whether this queue is empty.

{

QueueNode curr = front;

String res = "";

while (curr != null) {

res = res + curr.info + " ";

curr = curr.link;

Note that i could not complete the answers to all the question because the codes are above the brainly character limit, you might need to ask the question 2 and 3 separately.

Kindly check the outputs in the attached images below

5 0
4 years ago
Which of the following is NOT foundwithin the content pane?labelstitlebartextareasbuttons
HACTEHA [7]

Answer: Title bar

Explanation: Content pane is like a content box with certain features containing the object and knowledge about it. It is usually referred with several factors like labels , text, buttons etc to load the data in the dynamic way. These features are  present within the content pane. The only feature outside the content pane is title bar and thus is not found in content pane.

3 0
3 years ago
What are issues to consider when deciding to build software in-house or purchase commercial off-the-shelf software (cots)?
Scrat [10]
<span>On the computer there are always issues. For a developer to sit all day in front of a google that always invents things and the flashy images that disrupt everything. Googling on facebook is also an issue. Youtube, everything that contain flashy image is quite disruptive. If you think about content, maybe googling is less inventive. In a way it's nicer to buy applications but if you finally think of building it, there are always nicer ways of spending time. I prefer to go to seaside when I can.</span>
7 0
4 years ago
Joe's friend Bob told him about a new file sharing network. Joe found bootleg copies of the one of the Star Wars movies. Knowing
yawa3891 [41]
Not in fair use because he stealing the movie its called piracy
8 0
4 years ago
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