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4 years ago

PLEASE HURRY which solution shown below contains an error

Mathematics

2 answers:

bazaltina [42]4 years ago

8 0

the correct choice was the middle one

Harman [31]4 years ago

5 0

Answer:

(B) $\frac{1}{x+2} +\frac{1}{x+2} =\frac{2}{x+2} = \frac{1}{x+1}$

Step-by-step explanation:

We are given, $\frac{1}{x+2} +\frac{1}{x+2} =\frac{2}{x+2} = \frac{1}{x+1}$

⇒ $\frac{1}{x+2} +\frac{1}{x+2} =\frac{2}{x+2}[tex] [tex]\neq \frac{1}{x+1}$

Because on every simplification,you cannot remove 2 from the numerator.

therefore, option B shows an error.

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Helppppppppppppppppppppppppp

Gre4nikov [31]

Answer:

126°

Step-by-step explanation:

the internal sum of the angles is always 180

28+26= 54

180-54= 126

3 0

3 years ago

The cost is 284 the operating expenses are 43 the reduced price is 299 what is the operating loss

NISA [10]

Answer:

Step-by-step explanation:

operating loss is loss when value of operating loss is more than gross profit.

In the given problem

cost: 284

price : 299

profit = 299 - 284 = 15

but given that there is operating expense as well.

operating expenses = 43

as expense is greater than profit there is loss which is called operating loss.

operating loss = operating expense - profit = 43 - 15 = 28

Thus, operating loss is 28.

8 0

4 years ago

Mr. Jones has part of his $5,000 savings in an account that earned 7% interest and the rest in an account that earned 9% interes

Kipish [7]

Answer:z = $2286.5

y = $2713.5

Step-by-step explanation:

Let z represent the amount of money invested at the rate of 7%.

Let y represent the amount of money invested at the rate of 9%.

Mr. Jones has part of his $5,000 savings in an account that earned 7% interest and the rest in an account that earned 9% interest.. This means that

z + y = 5000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time

Considering the investment at the rate of 7%,

P = x

R = 7

T = 1

I = (z × 7 × 1)/100 = 0.07z

Considering the investment at the rate of 9%,

P = y

R = 9

T = 1

I = (y × 9 × 1)/100 = 0.09y

if his annual income from the total investment was 404.27, it means

0.07z + 0.09y = 404.27 - - - - - -1

Substituting z = 5000 - y into equation 1, it becomes

0.07(5000 - y) + 0.09y = 404.27

350 - 0.07y + 0.09y = 404.27

- 0.07y + 0.09y = 404.27 - 350

0.02y = 54.27

y = 54.27/0.02 = $2713.5

Substituting y = 2713.5 into z = 5000 - y, it becomes

z = 5000 - 2713.5 = $2286.5

4 0

4 years ago

Forty-eight percent of all registered voters in a particular state prefer life in prison without parole over the death penalty f

Gennadij [26K]

Answer:

0.63

Step-by-step explanation:

Given that:

$C \ = \ Californians \ (registered \ voters) \ preferrin g \ life \ in \ prison \ without \ parole \ over \ the \ death \\ penalty \ for \ a \ person \ convicted \ of \ first \ degree \ murder.$ P(C) = 0.48

L = Latino Californians

P(L) = 0.364

∴

P(C/L) = 0.63

7 0

3 years ago

Use the Divergence Theorem to evaluate the following integral S F · N dS and find the outward flux of F through the surface of t

Xelga [282]

Answer:

Result;

$\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = 32\pi$

Step-by-step explanation:

Where:

F(x, y, z) = 2(x·i +y·j +z·k) and

S: z = 0, z = 4 -x² - y²

For the solid region between the paraboloid

z = 4 - x² - y²

div F

For S: z = 0, z = 4 -x² - y²

We have the equation of a parabola

To verify the result for F(x, y, z) = 2(x·i +y·j +z·k)

We have for the surface S₁ the outward normal is N₁ = -k and the outward normal for surface S₂ is N₂ given by

$N_2 = \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} }$

Solving we have;

$\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{N}_1 d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \textbf{N}_2 d {S}$

Plugging the values for N₁ and N₂, we have

$= \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{(-k)}d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} } d {S}$

Where:

F(x, y, z) = 2(xi +yj +zk) we have

$= -\int\limits\int\limits_{S1} 2z \ dA + \int\limits\int\limits_{S2} 4x^2+4y^2+2z \ dA$

$= -\int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 2z \ dA + \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2+2z \ dA$

$= \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2 \ dxdy$

$= \int\limits^2_{-2} \frac{(16y^2 +32)\sqrt{-(y^2-4)} }{3} dy$

= 32π.

6 0

4 years ago