Bonita deposited $1300 into a bank account that earned 5.75% simple interest each year.
She earned $299 in interest before closing the account.
Principle = $1300
Rate = 5.75%
Simple interest = $299
Put all the value in the formulaTime = 4 years
Therefore
4 years was the money in the account .
Answer:
y=27 when x=2
Step-by-step explanation:
y varies inversely as the cube of x
y=k(1/X^3)
y=1 when x=6
y=k(1/X^3)
1=k(1/6^3)
1=k(1/216)
k=1÷1/216
K=1×216/1
k=216
find y when x=2
y=k(1/X^3)
y=216(1/2^3)
y=216(1/8)
y=216/8
y=27
Answer:
Step-by-step explanation:
a). Since, ΔABC ~ ΔWYZ
Their corresponding sides will be proportional.
--------(1)
By applying Pythagoras theorem in ΔABC,
AB² = AC² + BC²
BC² = AB² - AC²
BC² = (194)² - (130)²
BC² = 20736
BC = 144
From equation (1)
WY = 
WY = 
= 1.35
WZ = 
WZ = 
= 0.90
b). tan(A) = 
= 
= 
Since, ΔABC ~ ΔWYZ,
∠A ≅ ∠W
Therefore, tangent of angle A and angle W will measure .
Answer:
70 miles
Step-by-step explanation:
128-65/.9=m
128-65=63
63/.9=70 miles
70<or equal to m
Direct variation is a relation that has the form
y = kx
where k is the constant of proportionality.
If you are told that a relation is a direct proportion, and you are given one data point, you can find k. The you can write the equation of the direct relation.
Here is an example.
The price of gasoline follows a direct variation.
John bought 5 gallons of gas and paid $15.
a) Write an equation for the relation.
b) Using the relation you found, how much do 13.8 gallons cost?
Solution:
Since the relation is a direct variation, it follows the general equation of a direct variation:
y = kx
We are given one data point, 5 gallons cost $15.
We plug in 5 for x and 15 for y and we find k.
y = kx
15 = k * 5
k = 3
Now that we know that k = 3, we rewrite the relation using our value of k.
y = 3x
This is the answer to part a).
Part b)
We use our relation, y = 3x, and we plug in 13.8 into x and find y.
y = 3x
y = 3 * 13.8
y = 41.4
The price of 15 gallons of gas is $41.40.
