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rjkz [21]
3 years ago
10

Which percent is equivalent to the fraction 37/50

Mathematics
2 answers:
erik [133]3 years ago
8 0
times 37 x 2 and 50 x 2 = 74/100 so 74 100ths
aksik [14]3 years ago
4 0

\frac{37}{50}  =  \frac{74}{100}  = 74\%
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Calculate the equation of the line through the points (-1, 1), (4, 0), and (24, -4).
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y=-1/5x+4/5

Step-by-step explanation:

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4 years ago
Factors can be defined as ________ which divide the dividend without leaving any reminder​
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Factors can be defined as a number or algebraic expression which divide the dividend without leaving any reminder.

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A. (-10,-10)<br> B. (-1 /12, 9 1/2) <br> C. (1/2, 4) <br> D. (1,8)
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5 0
2 years ago
2(4x -4) + 8x = 2 (8x -3) solve for x please
Brrunno [24]

Answer:

No Solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

2(4x−4)+8x=2(8x−3)

Step 1: Simplify both sides of the equation.

2(4x−4)+8x=2(8x−3)

(2)(4x)+(2)(−4)+8x=(2)(8x)+(2)(−3)(Distribute)

8x+−8+8x=16x+−6

(8x+8x)+(−8)=16x−6(Combine Like Terms)

16x+−8=16x−6

16x−8=16x−6

Step 2: Subtract 16x from both sides.

16x−8−16x=16x−6−16x

−8=−6

Step 3: Add 8 to both sides.

−8+8=−6+8

0=2

Answer:

There are no solutions.

3 0
3 years ago
Can you tell me how to calculate R for below Matrix ?
scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}

Reduce the matrix in row echelon form as shown:

R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\

R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}

R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0
3 years ago
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