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d1i1m1o1n [39]
3 years ago
12

Evaluate for M = 10, N = -5, and P = -2

Mathematics
1 answer:
grigory [225]3 years ago
4 0
All of that multipied together will 100
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What is 10and 1 half divided by 7 eights​
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12

Step-by-step explanation:

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Pedro is building a playground in the shape of a right triangle. He wants to know the area of the playground to help him decide
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Answer:

Dimensions of rectangle:

Length =6 yards

Width=3 1/3 yards

Area of right triangle = 10 yd^2

Step-by-step explanation:

The right triangle has base as 6 yards and height as 3 1/3 of yards.

When we match this triangle with another right triangle to make  the rectangle is another right triangle with sides 6 yards and 3 1/3 yards.

I'll upload the file for work.

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Hello :) so I'm horrible at math, but since finals are coming up I want to calculate what my final grade will be if I were to fa
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Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

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3 years ago
Person who answers first I will give 30 points needed asap​<br>what is AoC<br>BoC <br>DoE<br>​
Degger [83]

Answer:

First of AOD is verticallly opposite to BoC which makes it 55°

Angle at AoC is 55°+55°+105° minus 360 which is 145° hope this helps

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