The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)
The midpoint of segment JL is
(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)
The midpoint of segment JK is
(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)
Answer: The coordinates are (-1, -3), (1, -3)
Answer:
<u>x^3-8x^2+5x+14</u>
Step-by-step explanation:
(x+1)(x-2)(x-7)
x^3-8x^2+5x+14
P = 2(L + W)
P = 200
L = W + 80
200 = 2(W + 80 + W)
200 = 2(2W + 80)
200 = 4W + 160
200 - 160 = 4W
40 = 4W
40/4 = W
10 = W.........the width is 10 yds
B=6 i believe! if you use the pythagorean theorem (a^2+b^2=c^2) then you should be able to turn 8^2 and 10^2 into 64 and 100, respectively. 100-64=36 and the square root of 36 is 6. you can plug it in by calculating 8^2 + 6^2, which equals 100! hope this wasn't too confusing XD