The median is the vertical line in the box
and the interquartile range is the length of the box itself
So the answer would be
B as its median is greater than 80 and it has the large <span>
interquartile range...</span>
I hope that
helps!
How to solve:
2(5y+3)-4(7y+1)=-88
10y+6-28-4=-88
-18y=-90
y=5
Solution for Y is 5
(I believe that is correct)
The given data of 1/4"=1' is a fixed ratio to be used to find the scale factor of the true measurement of the room. The given measurements are only on the drawing scale. To know the actual area of the room, find first the equivalent length and width. Then, you multiply them to obtain the area.
Through ratio and proportion:
<span>1/4"/1' = 312312"/length
</span>length = 1249248'
1/4"/1' = 514514"/width
width = 2058056'
Thus, the actual area of the bedroom is
A = length×width
A = (1249248')(2058056')
A = 2.57×10¹² square feet