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garik1379 [7]
3 years ago
11

Suppose a 15-minute call costs $5.26, and a 30-minute call costs $10.24. Find a formula relating time (in minutes) and cost (in

dollars).
How do you do this???
Mathematics
1 answer:
musickatia [10]3 years ago
4 0
If 15 minutes is $5.26 then 1 minute is 35¢ so the equation is y=.35t. But 30 minutes is $10.24 so 1 minute would be 34¢ so the equation would be y=.34t.
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viktelen [127]

Answer:

Tiffany ate 4 slices of pizza

Step-by-step explanation:

1/4 of 16 is 4

6 0
3 years ago
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Consider the line y=4x-4.
erica [24]

9514 1404 393

Answer:

  • parallel: y = 4x -6
  • perpendicular: y = -1/4x +27/4

Step-by-step explanation:

If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...

  y = mx +b . . . . . . . for slope m and y-intercept b

Solving for b gives ...

  b = y -mx . . . . . . . subtract mx from both sides.

The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.

<u>Parallel line</u>

  b = 6 -4(3) = 6 -12 = -6

  y = 4x -6

Perpendicular line

  b = 6 -(-1/4)(3) = 6 +3/4 = 27/4

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4 0
2 years ago
GETS BRAINILIST!!!A class has 6 boys and 14 girls. What is the ratio in simplest form that compares number of boys to total numb
FinnZ [79.3K]

Answer:

3:10

Step-by-step explanation:

1. Find the total number of students by doing

14 + 6= 20

2. Now make your ratio

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3. To make it in simplest form, divide both sides by 2

6 divided by 2 is 3

20 divided by 2 is 10

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3:10

7 0
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Dmitriy789 [7]

Answer: 7.2 months

Step-by-step explanation:

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f(x) = 100(1.25)^x

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500/100 = 1.25^x

5 = 1.25^x

log 5 =log 1.25^x

log 5 =x (log 1.25)

log 5 /log 1.25 =x

x = 7.2 months

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
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Step-by-step explanation:

F) Nine hundred thirty two and 76 hundredth

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