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Neporo4naja [7]
4 years ago
6

Suppose that the functions h and g are defined as follows.

Mathematics
1 answer:
never [62]4 years ago
3 0
(h/g)(-4)
\frac{(-4)-5}{(-4+2)(-4+3)}
Plug and chug
Should come out to be -4.5
\frac{x-5}{(x+2)(x+3)}
To find the values not in the domain, you must set each quantity in the denominator equal to zero and solve for x.
x+2=0   x+3=0
x≠-2      x≠-3
If x were either of these numbers, the denominator of the fraction would equal zero, which would give an undefined answer.
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