Answer:
yes they form a proportion
X + 5 + 11x = 12x + y
Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)
Subtract 12x from each side makes each zero.
5 = y
So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82
x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125
x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989
So we verified y = 5
Answer:
Step-by-step explanation:
<u><em>8).</em></u>
<em>(2)</em> × [ - 3 ]
4x + 3y = 1 ........ <em>(3)</em>
- 3x - 3y = - 6 .... <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
x = - 5
- 5 + y = 2 ⇒ y = 7
<em>( - 5 , 7 )</em>
<u><em>9).</em></u>
<em>(1)</em> ÷ [- 3]
3x - y = - 6 ......... <em>(3)</em>
2x + y = - 4 ........ <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
5x = - 10 ⇒ x = - 2
2(- 2) + y = - 4 ⇒ y = 0
<em>(- 2, 0)</em>
<u><em>10).</em></u>
<em>(2)</em> ÷ 10
x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>
0.6y - 2y = 14
- 1.4y = 14
y = - 10
x - 2(- 10) = 14 ⇒ x = - 6
<em>(- 6, - 10)</em>
Now is your turn, you can do it!!
<span>Exponent
is a number used to express shorter equation; it is a number that says how many
times you are going to multiply the base number.
</span><span>
Exponents have several laws, here are
some:
=> x^1 = x
=> x^0 = 1
=> x^-1 = 1/x
=> x^m x^n = X^m+n
=> x^m/x^n = x^m-n
And since we were asked to write an
expression with a negative exponent that has a value between 0 and ½
=> 2^ -2 = ½
</span>