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kakasveta [241]
4 years ago
13

Charlene made a square quilt block by piecing together four congruent isosceles triangles.The diagonal of the square is 6 in. Wh

at is the perimeter of the square in the simplest radical form ?

Mathematics
1 answer:
Amiraneli [1.4K]4 years ago
8 0

Answer:

The perimeter of the square 12√2 inches.

Step-by-step explanation:

See the diagram attached.

From the diagram, ABCD is the square and AC and BD are the diagonals and they intersect at O.

Now, given that, AC = BD = 6 in.

So, from Δ AOB, AO = 3 inches, BO = 3 inches, and AB = a unit (Side of the square)

{Since the diagonals of a square bisect each other perpendicularly}

So, we can write using the Pythagoras Theorem,  

AB² = AO² + BO²

⇒ a² = 3² + 3²

⇒ a = 3√2 inches.

Therefore, the perimeter of the square = 4a = 4 × 3√2 = 12√2 inches. (Answer)

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The <em>algebraic</em> expression x^{10/3} is equivalent to the <em>algebraic</em> expression x^{3}\cdot \sqrt[3]{x}. Thus, the right choice is option D.

<h3>How to apply power and root properties to rewrite a given expression</h3>

In this question we must apply the following set of <em>algebraic</em> properties to simplify a given expression:

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If we know that the given expression is x^{10/3}, then the equivalent expression is:

x^{10/3} = \sqrt[3]{x^{10}} = \sqrt[3]{x^{9}\cdot x} = \sqrt[3]{x^{9}}\cdot \sqrt[3]{x} = x^{3}\cdot \sqrt[3]{x}

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