Answer:
The perimeter of the square 12√2 inches.
Step-by-step explanation:
See the diagram attached.
From the diagram, ABCD is the square and AC and BD are the diagonals and they intersect at O.
Now, given that, AC = BD = 6 in.
So, from Δ AOB, AO = 3 inches, BO = 3 inches, and AB = a unit (Side of the square)
{Since the diagonals of a square bisect each other perpendicularly}
So, we can write using the Pythagoras Theorem,
AB² = AO² + BO²
⇒ a² = 3² + 3²
⇒ a = 3√2 inches.
Therefore, the perimeter of the square = 4a = 4 × 3√2 = 12√2 inches. (Answer)