Answer:
Area of the region = 15.03 in²
Step-by-step explanation:
Area of region between a regular hexagon with sides 6" and circle inscribed.
So Area of region = Area of regular hexagon - area of circle
Now area of regular hexagon = 
where a = side of the hexagon = 6"
Now area of regular hexagon = 
= 93.53 square in.
Area of circle inscribed = πr²
Here r is the radius of the circle = 
r = 5"
So area of the inscribed circle = π(5)² = 3.14(25) = 78.5 square in.
Now area of region = 93.53 - 78.5 = 15.03 in²
Area= length*width
width=W
W*(3W-4)=615
3W^2-4W=615
3W^2-4W-615=0
W=41
W=-45
But W cant be a negative number so it is 41m (width)
The length is (41*3)-4=119m (length)
This is a quadratic equation. There's a shortcut (two shortcuts really) called the Shakespeare Quadratic Formula (2b or -2b) applicable when the middle term is even:
OK, our problem is
Typically we'd write 
but the answers here don't so we won't either.
Answer: C and D
Answer:
7 ounces-4.58 = 1 ounce-0.654....
15 ounces-6.30= 1 ounce- 0.42
Explanation:
Divide 4.58 and 7 and divide 6.30 and 15.
And you get your answers.
I think im not really good with unit rate.
A segment bisector is a geometric figure that divides the line segment exactly in half.
Vertical angles theorem states that vertical angles, angles that are opposite to each other and formed by two intersecting straight lines, are congruent.
