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3 years ago

Find the possible values of s in the inequality 12s-20 <3s-25

Mathematics

1 answer:

GaryK [48]3 years ago

7 0

12s - 20 < 3s - 25 |+20

12s < 3s - 5 |-3s

9s < -5 |:9

s < -5/9

Answer: Any number from the set (-∞, -5/9).

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PLS HELP AND SHOW WORK I WILL GIVE BRAINLIEST + EXTRA POINTS WHOEVER SHOWS WORK......

andreyandreev [35.5K]

Answer:

1) b =

$\frac{13}{3}$

2)m = -2.5

3)y = 15

4)x=2

Step-by-step explanation:

subtract 8b from both sides
subtract 2 from both sides
divide both sides by 3
Substitute this value into the equation and if both sides are equal then it is the solution.

2)Simplifying

7m + 32 = 12 + -1m

Reorder the terms:

32 + 7m = 12 + -1m

Solving

32 + 7m = 12 + -1m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add 'm' to each side of the equation.

32 + 7m + m = 12 + -1m + m

Combine like terms: 7m + m = 8m

32 + 8m = 12 + -1m + m

Combine like terms: -1m + m = 0

32 + 8m = 12 + 0

32 + 8m = 12

Add '-32' to each side of the equation.

32 + -32 + 8m = 12 + -32

Combine like terms: 32 + -32 = 0

0 + 8m = 12 + -32

8m = 12 + -32

Combine like terms: 12 + -32 = -20

8m = -20

Divide each side by '8'.

m = -2.5

Simplifying

m = -2.5

3)Simplifying

16 + -5y = 1 + -4y

Solving

16 + -5y = 1 + -4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4y' to each side of the equation.

16 + -5y + 4y = 1 + -4y + 4y

Combine like terms: -5y + 4y = -1y

16 + -1y = 1 + -4y + 4y

Combine like terms: -4y + 4y = 0

16 + -1y = 1 + 0

16 + -1y = 1

Add '-16' to each side of the equation.

16 + -16 + -1y = 1 + -16

Combine like terms: 16 + -16 = 0

0 + -1y = 1 + -16

-1y = 1 + -16

Combine like terms: 1 + -16 = -15

-1y = -15

Divide each side by '-1'.

y = 15

Simplifying

y = 15

4)Simplifying

2x + -8x + 1 = 9 + -10x

Reorder the terms:

1 + 2x + -8x = 9 + -10x

Combine like terms: 2x + -8x = -6x

1 + -6x = 9 + -10x

Solving

1 + -6x = 9 + -10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10x' to each side of the equation.

1 + -6x + 10x = 9 + -10x + 10x

Combine like terms: -6x + 10x = 4x

1 + 4x = 9 + -10x + 10x

Combine like terms: -10x + 10x = 0

1 + 4x = 9 + 0

1 + 4x = 9

Add '-1' to each side of the equation.

1 + -1 + 4x = 9 + -1

Combine like terms: 1 + -1 = 0

0 + 4x = 9 + -1

4x = 9 + -1

Combine like terms: 9 + -1 = 8

4x = 8

Divide each side by '4'.

x = 2

Simplifying

x = 2

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3 years ago

The coordinates of a point on a coordinate grid are (−2, 6). The point is reflected across the x-axis to obtain a new point. The

Kipish [7]

So when you reflect the x-axis, you change the y negative. So (x,y) would be (x,-y). so it would be (-2, -6). If you want to reflect over the y-axis, it would be (-x, y).

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3 years ago

The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount o

IgorLugansk [536]

Answer:

y=0.2x+29

Step-by-step explanation:

Given that:

y is the total monthly of the A Fee and Fee plan.

x is the number of monthly minutes used.

If a customer uses 290 minutes, the monthly cost will be $87, we have the pair (290, 87)

If the customer uses 980 minutes, the monthly cost will be $225, this is the coordinate pair (980, 225).

We want to obtain an equation in the form: y=mx+b

First, let us determine the slope, m

Given points (290, 87) and (980, 225):

<u>Slope</u>

$m=\dfrac{225-87}{980-290} =\dfrac{138}{690}=0.2$

Next, we determine the y-intercept, b.

Substituting the pair (290, 87) and m=0.2 in y=mx+b, we obtain

87=0.2(290)+b

b=87-0.2(290)=29

Therefore, our equation in the form y=mx+b is:

y=0.2x+29

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3 years ago

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Mnenie [13.5K]

set up the triangle with the information given. then just solve for x.

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3 years ago

Let f be an exponential function and g be a logarithmic function.

love history [14]

Good evening ,

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Answer:

1) (f+g)(1) = e

2) (fg)(1) = 0

3) (3f)(1) = 3e

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Step-by-step explanation:

1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.

2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.

3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.

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