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anyanavicka [17]
3 years ago
8

If 3x = 27, then x =

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0

Answer:

x = 9

Step-by-step explanation:

3x = 27

3/3x = 27/3

x = 9

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If g(x) = 2x2 + 6x + 5, use synthetic division to find g(-5).
diamong [38]
<h3>Answer:  25</h3>

=================================================

Explanation:

Check out the image below. I've posted the synthetic division table. The value at the very end of the bottom row is the remainder. By the remainder theorem, this is exactly the value of g(-5).

Recall the remainder theorem says: If you divide p(x) by (x-k), then the remainder is p(k). In this case, k = -5 is our test root which is the value placed in the box on the left.

As a way to check the answer, we can say

g(x) = 2x^2 + 6x + 5

g(-5) = 2(-5)^2 + 6(-5) + 5

g(-5) = 25

So the answer is confirmed.

6 0
3 years ago
How do you round the area of a circle with 3.14?
kirill115 [55]

Answer:

(This is a example since you don’t have anything to round to)

Example Answer if the radius is 4 - 50.24

Step-by-step explanation:

Example Radius : 4

Area : 3.14

We have the mulitiply 3.14 times The Example Radius 2 times because The diameter of a circle is 2 times its radius.

( 3.14 x 4 x 4) 50.24

If you know the diameter, it’s a half or 1/2 as large.

Therefore, if the radius was 4, it would be 50.24.

Youre welcome :)

7 0
3 years ago
3w-13w= -20???????????
Akimi4 [234]
3w-13w=-20

Combine like terms

-10w=-20

divide both sides by -10

w=2
5 0
3 years ago
Estimate 19% of 44. 8, 9, 9.5, 10
Anna71 [15]
10% of 44 is 4.4 and 5% is 2.2 so 6.6 is 15% so an estimate of 8 is the most accurate
4 0
4 years ago
Three consecutive odd integers have a sum of 27. Find the integers.
jek_recluse [69]

\sf \bf {\boxed {\mathbb {GIVEN:}}}

Sum of three consecutive odd integers = 27

\sf \bf {\boxed {\mathbb {TO\:FIND:}}}

The values of the three integers.

\sf \bf {\boxed {\mathbb {SOLUTION:}}}

\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

Let us assume the three consecutive odd integers to be x, (x+2) and (x+4).

As per the condition, we have

Sum \:  \:  of \:  \:  the  \:  \: three \:  \:  consecutive \:  \:  odd \:  \:  integers  = 27

➺ \: x + (x + 2) + (x + 4) = 27

➺ \: x + x + 2 + x + 4 = 27

Now, collect the like terms.

➺ \: (x + x + x) + (2 + 4) = 27

➺ \: 3x + 6 = 27

➺ \: 3x = 27 - 6

➺ \: 3x = 21

➺ \: x =  \frac{21}{3} \\

➺ \: x = 7

Therefore, the three consecutive odd integers whose sum is 27 are \boxed{  7  }, \boxed{ 9   } and \boxed{ 11   } respectively.

\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}

⇢ 7 + 9 + 11 = 27

⇢ 27 = 27

⇢ L. H. S. = R. H. S.

\sf\blue{Hence\:verified.}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
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