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3 years ago

If y=x and y=2x + 1 What is the solution point??

Mathematics

2 answers:

cluponka [151]3 years ago

7 0

The answer is 1 because you have to Substitute Two form X then it would just be Then substitute 2 form 1 and you would get 1

Colt1911 [192]3 years ago

7 0

Answer:

(-1, -1)

Step-by-step explanation:

Given the two equations:

y = x and y = 2x +1, since both expressions are equal to 'y', you can set them equal to each other and first solve for x:

x = 2x + 1

Subtract '2x' from both sides: x - 2x = 1 or -x = 1

Divide both sides by '-1': -x/-1 = 1/-1 or x = -1

Since y = x, then y = -1

Solution point is (x, y) or (-1, -1)

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Aron charges an initial service fee of 10$ plus 15$ per hour , what is X?

Marysya12 [62]

Answer:

The linear function becomes:

y = 15x + 10

Here, 'x' is the number of hours, b=10 is the initial service fee i.e. $10, 15 is slope or rate of change, and 'y' is the cost.

Step-by-step explanation:

We know that the slope-intercept of a linear function is

$y = mx+b$

where m is the slope and b is the y-intercept

Note: Slope is also termed as the 'rate of change'.

Given that Aron charges an initial service fee of 10$.

Thus, the y-intercept = b = 10

As the rate of change = 15$ per hour

so the slope = m = 15

Therefore, the linear function becomes:

$y = mx+b$

y = 15x + 10

Here, 'x' is the number of hours, b=10 is the initial service fee i.e. $10, 15 is slope or rate of change, and 'y' is the cost.

For example, in one hour i.e. x = 1, the cost 'y' will be:

y = 15x + 10

y = 15(1) + 10

y = 25 + 10

y = $25

Therefore, in one hour (x=1), the cost will be: y = $25

7 0

3 years ago

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.

Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

$M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]$

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U = {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

$\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]$

The change of coordinate matrix is therefore,

$M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]$

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0

3 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Debora [2.8K]

Yo sup??

you can solve this quesion by having the knowledge of trigonometric ratios

let angle B be x, then

tanx=7/3

x=66.8

Hope this helps

4 0

3 years ago

What is 0.18 repeating simplified

Radda [10]

As a fraction it’s, 2/11

8 0

3 years ago

What is the percentage:<br><br> 16 out of 20

gtnhenbr [62]

16/20= .80
.80 x 100%
=80%

3 0

4 years ago