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zavuch27 [327]
4 years ago
15

Write a set of steps to describe how to use the elimination method with the system of equations.

Mathematics
1 answer:
grin007 [14]4 years ago
8 0
Idk idk idk I hav no idea
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What is the missing side length in the triangle?<br><br> plsss someone help!!
UkoKoshka [18]

Answer:

The measure of the missing side length = 45

Step-by-step explanation:

Pythagorean Theorem states: A² + B² = C²

28² + B² = 53²

784 + B² = 2809

B² = 2809 - 784

B² = 2025

B = \sqrt{2025}

B = 45

Therefore the measure of the missing side length = 45

Hope this helps!

6 0
3 years ago
Read 2 more answers
Aron ran 500 meter in 100 seconds. Find the speed in km per hour​
Free_Kalibri [48]

<em>solution</em>

<em>             time taken=100secs</em>

<em>             distance covered=500m=0.5km</em>

<em>As we know,</em>

<em>              speed=distance covered/time taken</em>

<em>                         =0.5km/100secs</em>

<em>                         =0.005km/sec</em>

<h2><em>                 </em></h2><h2><em>              SPEED IS 0.005KM/SEC</em></h2>
5 0
3 years ago
Angle A is 80, Angle C is 40 Figure out what measure the angle of B
maw [93]

Answer:

60

Step-by-step explanation:

The angle measures in a triangle always add up 180 degrees. 180-80-40=60

8 0
4 years ago
Necesito ayuda en numero 5
nikdorinn [45]
42,362 ÷ 81…..........
5 0
4 years ago
To determine whether or not they have a certain desease, 304 people are to have their blood tested. However, rather than testing
Artyom0805 [142]

Answer:

The expected number of tests necessary for the entire group of 304 people is 180.0325

Step-by-step explanation:

Probability of person being positive = p = 0.04

Probability of person being negative = q = 1-0.04=0.96

Number of people in each group = 19

We will use binomial over here

Probability of no test positive :

P(x=0) = ^{19}C_0 (0.04)^0 (0.96)^{19} =0.460419201958

P( at least one tests positive) = 1-P( no one tests positive)= 1-0.460419201958= 0.539580798042

Expected number of tests for each group = 1(0.460419201958)+20(0.539580798042) = 11.2520351628

Number of groups =\frac{\text{Total population}}{\text{no. of people in each group}}=\frac{304}{19}=16

Expected number of tests necessary for the entire group of 304 people:

=\text{Expected number of tests for each group} \times \text{No. of groups}

=11.2520351628 \times 16

=180.0325

Hence The expected number of tests necessary for the entire group of 304 people is 180.0325

7 0
3 years ago
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