1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nastasia [14]
4 years ago
5

HELPP ( Will give the brainliest answer) probability with a pair of dice

Mathematics
1 answer:
amid [387]4 years ago
5 0

Answer:

4. 2/6 (There are 6 sides. Only 2 are not factors.)

5. 3/12

6. 2/12

7. 3/12

8. 3/12

9. 6/23

10. 9/12

Step-by-step explanation:

These make sense if you do the math in your head.


Need brainliest, trying to rank up.



<u><em>Thank you in advance.</em></u>

You might be interested in
A 168-cm tall person is 2 cm in Ming’s model. How high should his model swing be if the actual swing is 231 cm high?
serious [3.7K]

Answer:

The model swing should be <u>2.75 cm</u> high.

Step-by-step explanation:

Given:

A 168-cm tall person is 2 cm in Ming’s model.  

If the actual swing is 231 cm high.

Now, to find how high should his model swing be.

Let the model swing be x\ cm.

So, 168 cm tall person is equivalent to 2 cm.

Thus, 231 cm actual swing is equivalent to x\ cm model swing.

Now, we get the height of the swing in the model by using cross multiplication method:

\frac{168}{2} =\frac{231}{x}

<em>By cross multiplication:</em>

⇒ 168x=462

<em>Dividing both sides by 168 we get:</em>

⇒ x=2.75\ cm.

Therefore, the model swing should be 2.75 cm high.

3 0
4 years ago
Will give Brainliest! if right!
Leno4ka [110]
I believe it is B, but I'm still unsure !
7 0
3 years ago
The semiannual tuition payment at a major university is expected to be $30,000 for the 4 years beginning 18 years from now. What
elena-14-01-66 [18.8K]

Answer:

$49,216.78

Step-by-step explanation:

A(n,k) = R[1-(1+i)^-n / i) (1+i)^-k

A = Present value of deferred annuity

R = Payment at the end of period

R = 30,000

i = 0.06 / 2

n = (4)*2 = 8

k = deferred period, (18)*(2) = 36

A(n,k) = 30,000*(1-(1+0.04)-^8 / 0.04)*(1+0.04)^-36

A(n,k) = 30,000*(1-(1.04)^-8 / 0.04)*(1.04)^-36

A(n,k) = 30,000*(1 - 0.730690205/0.04) * 0.24366872185

A(n,k) = 30,000*(0.269309795 / 0.04)*0.24366872185

A(n,k) = 30,000*6.732744875*0.24366872185

A(n,k) = 49216.78014700164

A(n,k) = $49,216.78

So the lump sum payment that the university accept now is $49,216.78

6 0
3 years ago
Cyliner A has a volume of 360 cm^3. Cylinder B has a base and height identical to that of Cylinder B, but leans to the right in
Marizza181 [45]
The volume of cylinder b is same as cylinder A = 360 cm^3
5 0
3 years ago
PLS HELP ME! . This pattern follows the rule multiply by 3, then subtract 4. What are the next two terms? 5, 11, 29
siniylev [52]

Answer:

Baka

Step-by-step explanation:

You silly baka lemme come over kitten and tutor you. 634 Dukanes Drive.

7 0
4 years ago
Read 2 more answers
Other questions:
  • Convert 45° from degrees to radians.
    5·2 answers
  • The sum of two consecutive integers is 89. find the integers.
    6·1 answer
  • How much paint would be needed to cover a sphere with a diameter of 3 centimeter
    6·1 answer
  • Beau is building 9 puppy bots and 6 kitty bots. Each bot needs 4 wheels. How many wheels does beau need in all
    6·1 answer
  • write an equation of the line passing through point P (3,-2)thats parallel to y=⅔x-1. how do i go about this equation ?
    9·1 answer
  • An arithmetic sequence has first term a = 5 and common difference d = 4. how many terms of this sequence must be added to get 41
    5·2 answers
  • Help would be much appreciated
    7·2 answers
  • 100,000^1/5 x a + 1,000,000^1/2 x a
    14·1 answer
  • Your first job is to make a graphical representation of the data. Many statisticians say that the first and most important step
    10·1 answer
  • If possible, give an example or if not possible, explain why<br>a whole number less than 0​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!