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3 years ago

F(x) = tan 2x , f'(x) = ....

Mathematics

2 answers:

mina [271]3 years ago

5 0

Using the chain rule : $[\tan(2x)]'=(2x)'\tan'(2x)=\frac{2}{\cos^2(2x)}$

Nady [450]3 years ago

3 0

$f(x)=\tan 2x\\
f'(x)=\sec^2 2x\cdot2=2\sec^2 2x$

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What are the coordinates of this point help plssssssssssssssss<br>

meriva

Answer:

(-2, -4)

Step-by-step explanation:

Use the (x,y) thing:

x = -2

y = -4

therefore, (-2, -4)

6 0

2 years ago

Out of a sample 650 high school students, 321 take the bus to school every day. construct a 99% confidence interval for the popu

gtnhenbr [62]

A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)

We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday

A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.

The confidence interval of proportions is given by:

π ± z √(π (1-π) /n)

π is the sample proportion.

z is the critical value.

n is the sample size.

For 99% confidence interval the value of z is 2.58

π = 321/650

The confidence interval is given by

=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)

= (0.493846 ± 0.050594)

=(0.4434 , 0.5443)

=(44.34 % , 54.43 %)

Hence a 99% confidence interval for the population mean of high school students that take the bus to school every day is ci=(44.34%, 54.43%)

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8 0

2 years ago

If n ≠ 0, which quadratic equation is written in standard form A.) x+x^2=n B) -x^2-x-n=0 C) x+x^2+n=0 D) x^2-x=n.Be sure to expa

Galina-37 [17]

Answer:

B. -x^2 - x - n = 0.

Step-by-step explanation:

In standard form the terms on the left side are in descending degree order, and the right side equals zero.

6 0

3 years ago

Austin is a human resources executive for a technology company. He is deciding between two types of plans for vacation allowance

ElenaW [278]

The question requires that we have to state the hypothesis:

null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.

<h3>A. How to state the hypothesis</h3>

H0: u1 < u2

H1: u1 > u2

The one tail test statistic is what is to be used here

<h3>B. standard error </h3>

$\sqrt{\frac{30.8}{17} +\frac{6.1}{15} }$

= 1.49

The df = 17 + 15 - 2

= 30

test statistic = 18.9 - 17.4 / 1.49

= 1.007

We have the critical value on excel as T.INV(0.9,30)

= 1.310

E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.

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2 years ago

Samantha saw 60 people.

Dmitry_Shevchenko [17]

Answer:

0.3

Step-by-step explanation:

Total number of cases = 60.

favourable number of cases = 18. (Since 18 of them are wearing green shirt)

As we know probability of an event is given by ,

P = Favourable number of cases divided by Total number of cases

Thus here,

P = $\frac{18}{60}$

= $\frac{3}{10}$ or 0.3

8 0

4 years ago