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lesya692 [45]
3 years ago
10

The amount of damage due to the 1868 Hayward earthquake is equal to the consequences that we expect to witness following the upc

oming next Hayward fault earthquake.
A. True
B. False
Geography
1 answer:
algol133 years ago
6 0

Answer:

Correct Answer:

B. False

Explanation:

The Hayward earthquake which happened in 1868 was minimal in terms of death of people (Approximately 5 ) and the properties destroyed. This is because, then, the area was sparsely populated.

<em>Currently, the area of the active earthquake is densely populated with buildings, and people. Should there be any earthquake there now, the damage would be devastating inclusive of the number of people dying being in high number.</em>

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Explanation:

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Studentka2010 [4]

Answer:

(a) Since both P and S wave travels the same distance, so it can be written as:    Δx = V₁t₁ = V₂t₂,

Where, V₁- Speed of S wave

            V₂- Speed of P wave

            t₁- time taken by S wave

            t₂- time taken by P wave

Therefore, t₁ > t₂ (since, time taken by S wave is longer than P wave)

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⇒ V₁t₂ + V₁ (90 sec) = V₂ (t₂)

⇒ V₂t₂ - V₁t₂ = V₁ (90 sec)

⇒ t₂ (V₂- V₁) = V₁ (90 sec)

⇒ t₂ = {V₁ (90 sec)} ÷ {(V₂- V₁)}

⇒ t₂ = {5.5 × (90 sec)} ÷ {(8.5 - 5.5)}

Therefore, t₂ = 165 sec

Since, Δx = V₁t₁ = V₂t₂

Now, Δx = V₂t₂ = (8.5 × 165 sec)

⇒ Δx = 1402 km

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