Simplify 6y^-4 with using positive exponents
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The difference between the maximum value of g(x) and the minimum value of f(x) is 5.
Given function is:
......(1)
The general form of a quadratic equation is with
.
As we know the minimum value of a quadratic function is when a>0
For f(x) a>0 so minimum value of f(x) = =7
From the graph, the maximum value of g(x) =12
So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5
Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.
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