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3 years ago

Find the distance d. Round your answer to the nearest tenth. Show the steps to solve.

Mathematics

1 answer:

Marina86 [1]3 years ago

7 0

Answer: $\sqrt{29}$

Step-by-step explanation: d is length of a hypotenuse in triangle. Use Pytago theorem d = $\sqrt{2^{2}+5^{2} } =\sqrt{29}$

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The mean of a set of eight numbers is 8 and the mean of a different set of twelve numbers is m. Given that the mean if the combi

Basile [38]

Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3

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3 years ago

Find the value of x in the equation below. 3x = 18

Oxana [17]

Answer:

x=6

Step-by-step explanation:

you need to get x alone so you divide by 3 on both sides

hope this helps!!! :)

example:

3x/3= 18/3

x=6

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3 years ago

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iragen [17]

Sorry don’t now the answer to this problem

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3 years ago

A lawn sprinkler sprays water 5 ft in every direction as it rotates. What is the area of the sprinkled lawn?

Karolina [17]

Answer:

78.57

Step-by-step explanation:

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2 years ago

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What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago