The Vertex of the parabola is V=(-5,-2)=(h,k)→h=-5, k=-2
This is a vertical parabola, then its equation has the form:
y=a(x-h)^2+k
Relacing h=-5 and k=-2
y=a(x-(-5))^2+(-2)
y=a(x+5)^2-2
When the x-value is -4, the y-value is 2. What is the coefficient of the squared expression in the parabola's equation:
a=?
x=-4, y=2→2=a(-4+5)^2-2
2=a(1)^2-2
2=a(1)-2
2=a-2
2+2=a-2+2
4=a
a=4
Answer: The coefficient of the squared expression in the parabola's equation is 4
Answer: Option B. 4
The value of y when x = 5 is 45
<h3><u>Solution:</u></h3>
Given that y varies directly with x. This can be written mathematically as:
y ∝ x
---- eqn 1
Where "k" is the constant of propotionality
Given y = 27 when x = 3. Substitute these values in eqn 1

<h3>k = 9</h3>
Substitute k = 9 in eqn 1
y = 9x ----- eqn 2
<u><em>To find: y = ? and x = 5</em></u>
Substitute x = 5 in eqn 2

Thus the value of y when x = 5 is 45
Factorize the numerator and denominator. You'll see that they both have a factor of 4 that can be canceled. The introduce a factor of 3 to change the denominator to 36.

we learned this in our lower i dont remember exactly but i think~
the probability that it will land on an even number will be 3 as there are 3 odd number and 3 even number