Answer: 20 fragments
Explanation:
This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.
- The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
- Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
- therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
- The expected number of fragments on the electrophoresis gel will be 20 fragments.
Answer:
4. Infrared Light 5. Ultra-Violet Light 6. ...damage...sunburn.
Explanation:
Looking at a Electromagnetic Spectrum will tell you the the visible and non visible. Hope this helps!
