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Leto [7]
3 years ago
11

Please help I have a test tomorrow!

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0
The answer for your quetion is letter a
wariber [46]3 years ago
7 0
3x-7>5
+7 +7
3x>12
÷3 ÷3
x<4
You might be interested in
Корень x-5=корень 3-x
Firlakuza [10]
√(x-5) = √(3-x)
|x-5| = |3-x|
x-5= 3-x
2x = 8
x=4
4 0
3 years ago
What is the measure of angle x?
Zigmanuir [339]
I need the picture in order to see what angle x is :)
8 0
3 years ago
Read 2 more answers
Wassily Leontief (1906-1999) was a Russian-born, American economist who, aside from developing highly sophisticated economic the
yKpoI14uk [10]

Answer:

The reason for the columns adding up to 1 is that each individual consumes a proportion or a fraction of the total quantity produced under each product category and every product is consumed.  There is no leftover.

When the proportions of all the individuals are added up, the sum is always 1 under each product category because each individual can only consume a part of the whole.

Step-by-step explanation:

a) Data and Calculations:

                        Food   Clothes  Housing  Energy  High Quality 100

                                                                                Proof  Moonshine

Farmer             0.25      0.15       0.25        0.18            0.20                    

Tailor                0.15      0.28       0.18         0.17            0.05

Carpenter        0.22      0.19       0.22        0.22           0.10

Coal Miner       0.20      0.15       0.20        0.28           0.15

Slacker Bob     0.18      0.23        0.15        0.15            0.50

Total                 1.00      1.00        1.00         1.00            1.00

6 0
3 years ago
HELP ASAP!!
olga2289 [7]

Answer:

62.5%

Step-by-step explanation:

150/240=0.625

you do 0.625x100 to get the percent.

8 0
3 years ago
Simplify sin q + cosq cotq.
IRINA_888 [86]
\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}
3 0
3 years ago
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