I got two solutions <span> n = 6<span> and n = -5</span></span>
That cant be a triangle because all the angles have to add up to 180
<span>True, as a postulate is the assumption of existence.</span>
2x+3y = -14y = 6x+22
Simplify
3Y=-14y=4x+22
Subtract 3y
-17Y=4X+22
Answer:
Step-by-step explanation:
RS Bisects PQ at T Given
PQ bisects RS at T Given
<RTQ = <PTS Vertically opposite Angles
PT = TQ Result of the given bisection
RT = TS Result of the given Bisection
ΔPTS ≡ ΔRTQ SAS. Note that the vertically opposite angles are between the two equal sets of lines.
