Answer:
mass of carbon monoxide
m = 36.55g
The chemical formula of carbon monoxide is,
C
O
.
Calculating the molar mass of carbon monoxide:
M
=
1
×
12
g
m
o
l
+
1
×
16
g
m
o
l
=
28
g
m
o
l
Calculating the number of moles:
n
=
m
M
=
36.55
g
28
g
m
o
l
=
1.305
m
o
l
Therefore, the are
1.305
moles in
36.55
grams of carbon monoxide
The 1st row has 15 chairs.
The 2nd row has 15 + 3 = 18 chairs.
The 3rd row has 18 + 3 = 15 + 2•3 = 21 chairs.
The 4th row has 21 + 3 = 15 + 3•3 = 24 chairs.
The pattern continues, so that the n-th row has 15 + (n - 1)•3 = 3n + 12 chairs.
If there are 15 rows, then the total number of chairs is
![\displaystyle \sum_{n=1}^{15} (3n + 12) = 3 \sum_{n=1}^{15} n + 12 \sum_{n=1}^{15} 1 = 3\cdot\frac{15\cdot16}2 + 12\cdot15 = \boxed{540}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%20%283n%20%2B%2012%29%20%3D%203%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%20n%20%2B%2012%20%5Csum_%7Bn%3D1%7D%5E%7B15%7D%201%20%3D%203%5Ccdot%5Cfrac%7B15%5Ccdot16%7D2%20%2B%2012%5Ccdot15%20%3D%20%5Cboxed%7B540%7D)
where we use the formulas
![\displaystyle \sum_{n=1}^N 1 = N](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5EN%201%20%3D%20N)
![\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csum_%7Bn%3D1%7D%5EN%20n%20%3D%20%5Cfrac%7BN%28N%2B1%29%7D2)
Answer:
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Explanation: