Answer: On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 8 pi.
Step-by-step explanation:
The function is y = sin(0.5*x)
We know that sin(0) = 0, so this graph must pass trough the point (0,0)
We know that the maximum of the sin(x) is 1, when x = pi/2. and the minimum is -1 when x = (3/2)*pi
but in our case the function is valuated in 0.5*x
then the maximum is when:
0.5*x = pi/2
x = pi/(2*0.5) = pi
and the minimum is when
0.5*x = (3/2)*pi
x = 3*pi
Now, knowing that sin(2*pi) = 0
The other 0 of the sin is when we have 0.5*x = 2*pi
x = 2*pi/0.5 = 4*pi
this means that in 4*pi we have one cycle, then in 8*pi we have tow cycles.
Then the correct option is:
"On a coordinate plane, a curve crosses the y-axis at (0, 0). It has a maximum of 1 and a minimum of negative 1. it goes through 2 cycles at 8 pi."
