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saw5 [17]
4 years ago
6

Need help please!

Mathematics
1 answer:
dimulka [17.4K]4 years ago
5 0

(1) QS bisecting <PQR implies <PQS = <SQR

(2) <PQS=45 deg and (1) imply <SQR also = 45 deg

(3) from (2) it follows that <PQR = <PQS + <SQR = 45 + 45 deg = 90 deg and therefore the triangle is right-angled

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Determine which equation is written in function form:
Mila [183]

<em>Greetings from Brasil... </em>

A 1st degree function can be written in two ways:

F(X) = AX + B

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Y = AX + B

note that F(X) = Y

So, looking at the alternatives in the question, only Y = 7X/3 - 8 is equivalent to Y = AX + B, where:

A = 7/3

B = - 8

then

\large{\boldsymbol{\mathbf{Y = \frac{7X}{3}-8\Leftrightarrow Y=AX+B}}}   <em>a function of the 1st degree</em>

answer:

<h2>Y = (7/3)X - 8</h2>
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CALLING ALL MATH GENIUS!!! Help! Please!
IrinaK [193]

2) 7/8+1/3+1/2=1\frac{17}{24}, so your answer is A

3) 1/9+1/12, it's LCD (lest common denominator) is 36, \frac{1*4}{9*4} + \frac{1*3}{12*3} = \frac{4}{36} + \frac{3}{36} = \frac{4+3}{36} = \frac{7}{36} so your answer is also A

4) 13+\frac{1}{4} +\frac{2}{3} find the Least Common Multiple (LCM) of

4, and 3, which is 12. Now make the denominators the same as the LCD, 13+\frac{1*3}{4*3} +\frac{2*4}{3*4}. Now Simplify; 13+\frac{3}{12} +\frac{8}{12} =13+\frac{3+8}{12} =13\frac{11}{12}, D is your answer.

5) LCD=9, so make the denominators the same as the LCD, \frac{4}{9} - \frac{1*3}{3*3} = \frac{4}{9} - \frac{3}{9} = \frac{4-3}{9} =\frac{1}{9}. Your answer is B.

6) 30-22\frac{5}{6}, (use.the.rule...a\frac{b}{c}=\frac{ac+b}{c}...because.22\frac{5}{6}.is.an.improper.fraction)

30-\frac{22*6+5}{6} =30-\frac{132+5}{6}=30-\frac{137}{6} = make the denominators the same 30*\frac{6}{6} -\frac{137}{6} =\frac{180}{6} -\frac{137}{6} =\frac{43}{6} =7\frac{1}{6}

7) 9\frac{5}{12} is an improper fraction, so you the previous rule I said to use for improper fractions.

\frac{9*12+5}{12} -4\frac{2}{3} =\frac{108+5}{12}-4\frac{2}{3}, also 4\frac{2}{3} is an improper fraction so use the rule again.

\frac{113}{12} -\frac{12+2}{3} =\frac{113}{12} -\frac{14}{3}, LCD=12

Make the denominators the same \frac{113}{12}-\frac{14*4}{3*4}=\frac{113}{12}-\frac{56}{12} =\frac{113-56}{12} =\frac{57}{12}=\frac{19}{4}=4\frac{3}{4}, the answer is D

8) 21\frac{7}{9}, improper fraction

\frac{21+19+7}{19} -6\frac{8}{19} =\frac{399+7}{19} -6\frac{8}{19} = \frac{406}{19} -6\frac{8}{19}

6\frac{8}{19} is an improper faction

\frac{406}{19}-\frac{6*19+8}{19}  =\frac{406}{19} -\frac{114+8}{19} =\frac{406}{19} -\frac{122}{19} =\frac{406-122}{19}=\frac{284}{19}=14\frac{18}{19}, the answer is B.

9) \frac{8}{9} -\frac{6}{9} =\frac{2}{9}, You're trying to see how much farther he ran on Monday compared to Wednesday, so Monday goes first.

10) \frac{3}{4} -\frac{1}{8} =\frac{5}{8}, You're trying to see how much more you need, so you need to subtract 1/8 (what you already have) and 3/4 to see how much you need left.

11) You're tyring to see how much she need all together, so you're looking for the sum, which is 12\frac{3}{8}, so the answer is C.

12) You're seeing how much he grew over the past years, so you'll be looking for the sum (addition) 1\frac{3}{4}+ 2\frac{2}{3} =4\frac{5}{12}

19) In this problen, Claude used some of his ribbon, which in turn decreased the amount he has left, so you are looking for the difference (In this case, what he has now, vs what he originally had.) 5\frac{1}{2} -4\frac{2}{3}= \frac{5}{6}, your answer is C.

20) Find the time it takes in all the routes by subtracting the time you leave to the time you get there, the answer is route four because it is 2 hours and 5 minutes.

Hope this helps, have a BLESSED and wonderful day, as well as a safe one!

-Cutiepatutie ☺❀❤

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