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Sedbober [7]
3 years ago
14

Solve y = x2 +11 for x.

Mathematics
1 answer:
otez555 [7]3 years ago
4 0
The answer would be C. X= y - 11
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Tubas, trombones and French horns are bass instruments. Fully stretched out, the length of a tuba is 18 feet. The length of a tr
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What I would do is convert the fractions to decimals (just personal preference) making the trombone 8.93 feet and the french horn 17.21 feet. The tuba would be 0.79 feet longer than the french horn, and the french horn would be 8.23 feet longer than the trombone. However, if you need the answer to remain a fraction, the tuba would be 11/14 feet longer than a french horn, and a french horn would be 8 3/14 feet longer than a trombone.
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Find the next three terms of the sequence.
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Step-by-step explanation:

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The measure of angle 6 is 48 degrees, what are the measures of the remaining angles?
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5 and 8and 1 and 4= 132
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Find the slope of each line that passes through each pair of points The points (3, 5) and (-2, 10) lie on a line. The points P (
Pavel [41]

Answer:

  1. m = -1
  2. m = 0

Step-by-step explanation:

1.

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(3,\:5\right),\:\left(x_2,\:y_2\right)=\left(-2,\:10\right)\\\\m=\frac{10-5}{-2-3}\\\\m=\frac{5}{-5}\\\\simplify\\\\m=-1

2.

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(5,\:-7\right),\:\\\left(x_2,\:y_2\right)=\left(-2,\:-7\right)\\\\m=\frac{-7-\left(-7\right)}{-2-5}\\\\m=\frac{-7+7}{-7} \\\\m = \frac{0}{7}\\\\Simplify\\\\m =0

3 0
3 years ago
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
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