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Sedbober [7]
3 years ago
9

Which list shows numbers ordered least to greatest? A. 1.01, 21/19, 1.01 repeated B. 21/19, 1.01, 1.01 repeated C. 1.01, 1.01 re

peated, 21/19 D. 1.01 repeated, 1.01, 21/19
Mathematics
1 answer:
Finger [1]3 years ago
5 0

Given:

The list of numbers have three numbers 1.01,\dfrac{21}{19},1.011111...

To find:

The correct list which shows numbers ordered least to greatest.

Solution:

First we have to convert all numbers in decimal form.

Here, two numbers are already in decimal form.

\dfrac{21}{19}=1.10526315789


All numbers before decimal are equal, i.e., 1. So, check the numbers after decimal.

Two numbers 1.01,1.011111... have 0 after decimal and 1.10526315789
 has 1 after decimal. So, 1.10526315789=\dfrac{21}{19}
 number is greatest.

Now, compare the digit on hundredth place (second place after decimal).

Both numbers 1.01 and1.011111... have 1 on hundredth place.

Now, compare the digit on thousandth place (third place after decimal).

Number 1.01 have nothing on thousandth place. So, it is 0.

Number 1.011111... has 1 on  thousandth place. So, 1.011111... is greater than 1.01.

Now, the arrangement in ordered least to greatest is

1.01,1.011111...,\dfrac{21}{19}

Therefore, the correct option is C.

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Choose the correct solution and graph for the inequality.
Maslowich

D. x is greater than or equal to -8

Explanation:

The inequality given by the problem is:

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In order to solve it, we must do the following steps:

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3 years ago
For the function f(x) = -x^3 + 2x^2 + x - 2
kaheart [24]

Answer:

Step-by-step explanation:

a)

f(1)=-1^3+2*1^2+1-2=-1+2+1-2=0\\\\

b)

Rationnel roots are divisor of -2: -1,1,-2,2

f(-1)=-(-1)^3+2*(-1)^2+(-1)-2=1+2-1-2=0\\\\\begin{array}{c|cccc}&x^3&x^2&x&1\\---&---&---&---&---\\&-1&2&1&-2\\x=1&&-1&1&2\\&-1&1&2&0\\\\x=-1&&1&-2\\&-1&2&0\\---&---&---&---&---\\\end {array}\\\\\\f(x)=-x^3+2x^2+x-2=(x-1)(x+1)(-x+2)\\\\

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