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3 years ago

Simplify the question.

Mathematics

1 answer:

Anit [1.1K]3 years ago

3 0

It is the 3rd answer, hope this helps.

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(0,0) and (-4,-5) in point slope form (please show work if possible)

Kaylis [27]

I think formula is y2-y1 divided by x2-x1 so if im correct
-5/-4

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3 years ago

Read 2 more answers

Find the three arithmetic means between -5 and -25.

inn [45]

The answer you are looking for is: -15.
I hope this helps.

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3 years ago

Given that (-4,2) is on the graph of f(x) find the corresponding point for the function -1/2f(x)

Aleks [24]

Answer:

The corresponding point is (-4.-1)

Step-by-step explanation:

we know that

The point (-4,2) is on the graph of f(x)

For x=-4

f(x)=2

therefore

For x=-4

-(1/2)f(x)=-(1/2)*2=-1

The corresponding point is (-4.-1)

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3 years ago

Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.

natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is $y=x-x^2-2$ and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

$y'=1-2x$

It can be written as

$\frac{dy}{dx}=1-2x$

Use variable separable method to solve this differential equation.

$dy=(1-2x)dx$

Integrate both the sides.

$\int dy=\int (1-2x)dx$

$y=x-2(\frac{x^2}{2})+C$ $[\because \int x^n=\frac{x^{n+1}}{n+1}]$

$y=x-x^2+C$ ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

$-2=1-(1)^2+C$

$-2=1-1+C$

$-2=C$

The value of C is -2. Substitute C=-2 in equation (1).

$y=x-x^2-2$

Therefore the solution of the given initial value problems in explicit form is $y=x-x^2-2$ .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

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3 years ago

Find the value of x. Then find the measure of each label length.

sweet-ann [11.9K]

Should be somewhere around there either way for 9. the angles are the same because you see the arrows on the parallel lines 8. I'm not quite as sure about

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3 years ago