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Art [367]
3 years ago
11

What is the product?

Mathematics
2 answers:
patriot [66]3 years ago
8 0

Answer:

Answer is D

Step-by-step explanation:

ZanzabumX [31]3 years ago
6 0
To get the answer to this equation you first cancel out the 6! ;)

(x^2-1)(6x-1) / (x+1)

Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1

(x^2-1^2)(6x-1) / (x+1)

Then use the difference of squares!

(x+1)(x-1)(6x-1) / (x+1)

LASTLY cancel "x+1" !

so ur answer is (x-1) (6x-1)

That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)

YW!!!  ;) 
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Please answer ASAP! <br> All help is deeply appreciated!
Darina [25.2K]

Answer:

I am going to have to go with B. (How many text messages do you send each day?) This will get you the data needed because it is specific. D would also work but I went with C because D is less informative and less specific about how often people use their phones. Hope that this helped! Please tell me if you have any more questions! Have a great day!

4 0
3 years ago
The vertex of ∠ABC is <br> A<br> B <br> C
PSYCHO15rus [73]

Answer:

The vertex is b

Step-by-step explanation:

3 0
3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
Problem 1. (1 point) A steel ball weighing 128 pounds is suspended from a spring. This stretches the spring 128101 feet. The bal
stepladder [879]

Answer:

seeed

Step-by-step] explanation:

ddd~!`

7 0
3 years ago
A geometric sequence has these properties: a^1=2
grin007 [14]
The third term of the sequence is 20
3 0
3 years ago
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