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olga55 [171]
4 years ago
14

A cylindrically shaped space station is rotating about the axis of the cylinder to create artificial gravity. The radius of the

cylinder is 82.5 m. The moment of inertia of the station without people is 3.00 ???? 10 9 kg ???? m2. Suppose that 500 people, with an average mass of 70.0 kg each, live on this station. As they move radially from the outer surface of the cylinder toward the axis, the angular speed of the station changes. What is the maximum possible percentage change in the station’s angular speed due to the radial movement of the people?
Mathematics
1 answer:
erica [24]4 years ago
5 0

Answer:

8%

Step-by-step explanation:

The maximum change happens when all 500 people moves form outer surface to the station center. When all of them are at the surface, the total moment of inertia is:

I = I_s + 500I_p = 3*10^9 + 500m_pr_p^2=3*10^9 + 500*70*82.5^2=3.24*10^9

When they are at the axis, the total moment of inertia is only the station's, which is 3*10^9

By the law of angular momentum conservation:

I_1\omega_1 = I_2\omega_2

\omega_2/\omega_1 = I_1/I_2 = \frac{3.24*10^9}{3*10^9} = 1.08

So the angular speed changes by 0.08 of itself, or 8%

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Answer:

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Step-by-step explanation:

6 0
3 years ago
Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.
SCORPION-xisa [38]

Answer:

The solutions are x=-3,\:x=3

Step-by-step explanation:

To factor this cubic polynomial x^3+3x^2-9x-27 you must:

  • Group the polynomial into two sections

x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)

  • Factor out -9 from (-9x-27)

(-9x-27)=-9\left(x+3\right)

  • Factor out x^2 from (x^3+3x^2)

(x^3+3x^2)=x^2\left(x+3\right)

x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)

  • Factor out common term x+3

-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)

x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)

  • Factor x^2-9

x^2-9=\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0

  • Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}

The solutions are

x=-3,\:x=3

3 0
3 years ago
Hi I need help on this I've been working on it for about 20 minutes now please help :)
Mama L [17]

Answer:

V = 4 2/3 units ^3

Step-by-step explanation:

We are given the area of the back rectangle

V = BH where B is the area of the base

V = 3 1/3 * 1 2/5

Rewriting the mixed numbers as improper fractions

V = 10/3 * 7/5

V = 70/15

Simplifying

V = 14/3

Changing back to a mixed number

V = 4 2/3 units ^3

5 0
2 years ago
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alexdok [17]
Yes, your answer is correct
5 0
3 years ago
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almond37 [142]

x - √3y - 4 = 0 → <u>Choice</u><u> </u><u>A</u>

Step-by-step explanation:

x - 4 = √3y

x - 4 <u>- √3y</u> = √3y <u>- √3y</u>

x - 4 - √3y = 0

x - √3y - 4 = 0

4 0
3 years ago
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