What isthe turning point of the parabola equation isY=(x+2)(x-8)
1 answer:
Answer:
(3, - 25 )
Step-by-step explanation:
Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0
The the x- coordinate of the turning point is
x = -
Given
y = (x + 2)(x - 8) ← expand factors using FOIL
= x² - 6x - 16 ← in standard form
with a = 1 and b = - 6, thus
x = - = 3
Substitute x = 3 into the equation for corresponding value of y
y = (3 + 2)(3 - 8) = 5(- 5) = - 25
turning point at (3, - 25 )
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Turn both equations into slope-intercept form [ y = mx + b ].
x + 3y = 3
~Subtract x to both sides
3y = 3 - x
~Divide 3 to everything
y = 1 - x/3
~Reorder
y = -1/3x + 1
4x + 3y = -6
~Subtract 4x to both sides
3y = -6 - 4x
~Divide 3 to everything
y = -2 - 4x/3
~Reorder
y = -4/3x - 2
Graph of the equations will be shown below. Note that the solution of graphing two equations will be where both equations intersect. Both lines intersect at (-3, 2), hence making that the solution.
Best of Luck!
Answer:
-1.1, 6.1
Step-by-step explanation:
-2X^2+10X+14=0
(-2X^2+10X+14)/-2=0
X^2-5X-7=0
Then use the quadratic formula because you can't factor
Fill in the equations and solve. One should have the plus and the other should have the minus and that's how you get the 2 different answers.
A=1
B=-5
C=-7
