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nexus9112 [7]
3 years ago
12

Tell me what the answer 54x65!

Mathematics
2 answers:
Ray Of Light [21]3 years ago
8 0

Answer:

3510

Step-by-step explanation:

liubo4ka [24]3 years ago
5 0

Answer:

283829 grfg gfdgg dfgfdgdfgdf

Step-by-step explanation:

322332fcv fghfgd fdg fd

because i think so fdsfdsfs

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How do you solve 3x+7=x
vredina [299]
3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: \frac{7}{-2} = x
Fourth, simplify \frac{7}{-2} to -\frac{7}{2} / Your problem should look like: - \frac{7}{2} = x
Fifth, switch sides. / Your problem should look like: x = -\frac{7}{2}

Answer as fraction: -\frac{7}{2}
Answer as decimal: -3.5


8 0
3 years ago
Read 2 more answers
Question 6 (Essay Worth 2 points)<br> Find all polar coordinates of point P = (2, 14°).
andrey2020 [161]

Answer:

(2,14°+360n) and (-2,14°+(2n+1)180°)

Step-by-step explanation:

You start out with (2, 14°)

The polar coordinate can be written as (r, 0) = (r, 0+2nπ) or

(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r,  the polar coordinate can be written as

p=(2,14°) = (2,14°+360n°), where n is any integer.

For the negative value of r ,  the polar coordinate can be written as

p=(2,14°) = (-2,14°+(2n+1)180°), where n is any integer.

All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

4 0
3 years ago
6
IgorC [24]

Answer:

12 less than or equal to 2

Step-by-step explanation:

7 0
3 years ago
How do you solv this step by step and explain and help me get the answers
Dafna1 [17]

Answer:

25

Step-by-step explanation:

125^2=125*125=15625

125^4/3=cube root of 125^4=cube root of 244240625=625

15625/625=25

3 0
3 years ago
19.2 cm<br> 13.5 cm<br> What is the area
Slav-nsk [51]

Answer:

259.2 cm

Step-by-step explanation:

Just multiply the two numbers

4 0
3 years ago
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