3 years ago

How many solutions does y=2x+2,4x-2y=4 have?

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

It has No solutions. .

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Determine the type and number of solutions of 4x^2-5x+1=0.

Arlecino [84]

4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9

x = - b ± √Δ / 2.a
$x = \frac{-5\± \sqrt{9} }{2*4}$
$x = \frac{-5\±3}{8}$
$x' = \frac{-5-3}{8} = \frac{-8}{8} = -1$
$x' = \frac{-5+3}{8} = \frac{-2}{8} (\div2) = \frac{-1}{4}$

A. Two real solutions (x' = -1 and x'' = -1/4)

4 0

3 years ago

Order these numbers in ascending order. -11/3, 90%, 89/4, 2

Delicious77 [7]

Answer:

$- \frac{11}{3} \: \: » \: \: 90\% \: » \: \: 2 \: \: » \: \: \frac{89}{4}$