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Vikki [24]
3 years ago
13

Are y=2x+6 and 6t=2x+9 perpendicular

Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Using the slope-intercept form, the slope is 2 2 . The equation of a perpendicular line to y=2x+9 y = 2 x + 9 must have a slope that is the negative reciprocal of the original slope.

Missing: 6t= ‎| Must include: 6t=

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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
zack bought a coat for $ 69.78 he paid with a $100 bill and received $26.73 in change. how much was the sales tax ?
Ratling [72]

The sales tax was $3.49.

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Hope that helped!

5 0
2 years ago
What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?
NeTakaya

Answer:

The quotient of the expression will be (x² - 2x + 3).

Step-by-step explanation:

The given expression is (x³ - 3x² + 5x - 3) ÷ (x - 1)

Now we will use the synthetic division method to solve this question.

We will note down the coefficient of the expression as below

                         x³               x²            x               constant

                         1               (-3)            5                   -3

                 1       1       (1×1-3)=(-2)   [1×(-2)+5]=3     (1×3-3)=0

Therefore (x -1) is a perfect zero factor.

Now we can easily say that coefficient of the expression is [1.x² + (-2)x + (3)]

and remainder is 0.

Or in more simplified way coefficient of the expression will be

(x² -2x + 3).

8 0
3 years ago
Read 2 more answers
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