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3 years ago

BEST ANSWER GETS BRAINLIEST What is 14b + 6b - 12

Mathematics

1 answer:

Andrews [41]3 years ago

3 0

14b + 6b - 12

(14b + 6b) - 12 collect like terms

20b - 12 << your answer

hope this helps, God bless!

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A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

boyakko [2]

Answer:

Part 1) On square 18 should be place $131,072\ grains$

Part 2) The total number of grains of wheat is $18,446,744,073,709,551,615\ grains$

Part 3) The total weight is $W=2,635,249,153,387,079\ pounds$

Step-by-step explanation:

we know that

In a Geometric Sequence each term is found by multiplying the previous term by a constant

Part A) How many grains of wheat should be placed on square 18?

In this problem we have

a1=1

a2=2

a3=4

a4=8

The common ratio (r) is equal to

a2/a1=2/1=2

a3/a2=4/2=2

a4/a3=8/4=2

r=2

the explicit rule for the nth term is equal to

$an=a1(r^{n-1} )$

For n=18

we have

a1=1

r=2

substitute

$a18=(1)(2^{18-1})$

$a18=(2^{17})$

$a18=131,072\ grains$

Part 2) Find the total number of grains of wheat on the board

we know that

The formula of the sum in a geometric sequence is equal to

$S=a1\frac{1-r^{n}}{1-r}$

we have

a1=1

r=2

n=64

substitute

$S=(1)\frac{1-2^{64}}{1-2}$

$S=\frac{1-2^{64}}{-1}$

$S=18,446,744,073,709,551,615\ grains$

Part 3) Find the total weight in pounds. (Assume that each grain of wheat weighs 1/7000 pound.)

To obtain the total weight multiply the total grains by (1/7,000)

$W=2,635,249,153,387,078.8\ pounds$

Round to the nearest pound

$W=2,635,249,153,387,079\ pounds$

8 0

2 years ago

Which of the following equations has a solution x = 4? Select all that apply.

natka813 [3]

Answer:

$-2(3x - 4) = -16$ and $20- 15x = 6 - 2(4x + 7)$

Step-by-step explanation:

Given

$-2(3x - 4) = -16$

$\frac{1}{2}(10x + 2) = 6$

$20- 15x = 6 - 2(4x + 7)$

$\frac{1}{3}(9x - 12) + 6=-10$

Required

Equations with $x = 4$ as a solution

$-2(3x - 4) = -16$

Divide both sides by -2

$3x - 4 = 8$

Add 4 to both sides

$3x - 4 +4= 8+4$

$3x =12$

Divide both sides by 3

$x = 4$

$\frac{1}{2}(10x + 2) = 6$

Multiply both sides by 2

$10x + 2 = 12$

Subtract 2 from both sides

$10x + 2 -2= 12-2$

$10x = 10$

Divide both sides by 1

$x = 1$

$20- 15x = 6 - 2(4x + 7)$

Open bracket

$20 - 15x = 6 - 8x - 14$

Collect like terms

$8x - 15x = 6 - 14 - 20$

$-7x = -28$

Divide both sides by -7

$x = 4$

$\frac{1}{3}(9x - 12) + 6=-10$

Subtract 6 from both sides

$\frac{1}{3}(9x - 12) + 6-6=-10-6$

$\frac{1}{3}(9x - 12) =-16$

Multiply both sides by 3

$9x - 12 = -48$

Add 12 to both sides

$9x - 12 +12= -48+12$

$9x = -36$

Divide both sides by 4

$x =-4$

$-2(3x - 4) = -16$ and $20- 15x = 6 - 2(4x + 7)$ have $x = 4$ has a solution

6 0

2 years ago

Read 2 more answers

If z1 = 12(cos55° + isin55°) and z2 = 4(cos95° + isin95°), then |z1z2|= ???

zaharov [31]

$\bf \begin{cases}
z_1=12[cos(55^o)+i~sin(55^o)]\\\\
z_2=4[cos(95^o)+i~sin(95^o)]
\end{cases}\\\\
-------------------------------$

$\bf ~~~~~~\textit{ product of two complex numbers}\\\\
{{ r_1}}[cos({{ \alpha}})+isin({{ \alpha}})]\quad \cdot \quad {{ r_2}}[cos({{ \beta}})+isin({{ \beta}})]
\\\\\\
\implies {{ r_1\cdot r_2}}[cos({{ \alpha}} + {{ \beta}})+isin({{ \alpha}} + {{ \beta}})]\\\\
-------------------------------\\\\
z_1\cdot z_2\implies 12\cdot 4[cos(55^o+95^o)+i~sin(55^o+95^o)]
\\\\\\
48[cos(150^o)+i~sin(150^o)]
\\\\\\
|~48[cos(150^o)+i~sin(150^o)]~|\implies 48[cos(150^o)+i~sin(150^o)]$

6 0

2 years ago

Inge and Oleg were helping their mom clear rocks from a pasture using a wheelbarrow. If each load of rocks they carried to the f

zzz [600]

Answer:

20 loads

Step-by-step explanation:

2000 divided by 100 is 20

5 0

2 years ago

Read 2 more answers

What equation represents the nth term of the sequence {2, -1, -4, -7, ...}

user100 [1]

You got a picture??????

7 0

2 years ago