Answer:
40m
Explanation:
u=10m/s, h=20m, g=?, s=h, v=0
solve for g first
v²=u²+2gs
0=10²+2×g×20
0=100+40g
-100=40g
g=-2.5m/s²
solve for time t
v=u+gt
0=10+(-2.5t)
-10=-2.5t
divide both side by -2.5
-10/-2.5=t
t=4s
lastly, solve for x(distance)
x=ut+1/2gt²
x=10×4+1/2×2.5×16
x=40+(2.5×8)
x=40+20=60
then subtract the d1(initial) from d2(final) distance
x=60-20=40m
Based on the information given, the value of the area of the irregular figure will be 13.7 ft².
<h3>How to calculate the area.</h3>
From the complete question, the area of a triangle will be:
= 0.5 x base x height
= 0.5 x 3.6 x 4.8
= 8.64 ft²
Area of the semicircle = 0.5πr²
Area of the semicircle = 0.5 x 3.14 x 1.8²
Area of the semicircle = 5.09 ft²
Area of the irregular figure = Area of the semicircle + Area of the triangle
= 5.09 ft² + 8.64 ft²
= 13.73ft² = 13.7 ft²
Learn more about area on:
brainly.com/question/12327739
The magnitude of an object's charge can either increase or decrease the attraction/ repulsion between another object. The larger the difference of the two object's charges, the stronger opposite charges attract, and the stronger like charges repel.
Answer:
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Explanation: